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Field form factor and choice of poles

Short answer

Field form factor ψ = Bav/Bg ≈ pole arc/pole pitch, typically 0.64–0.72. Number of poles depends on frequency (25–50 Hz), iron and copper weight, armature reaction, current per brush arm, commutator length, flashover limits, and labour cost.

What is field form factor of a dc machine? What are the factors to be considered while selecting the number of poles in a dc machine? Explain.

Field form factor

The field form factor ψ\psi (or KfK_f) is the ratio of average gap flux density over a pole pitch to the maximum gap flux density:

ψ=BavBg≈pole arcpole pitch\psi = \frac{B_{av}}{B_g} \approx \frac{\text{pole arc}}{\text{pole pitch}}

Its usual value is 0.64–0.72.

Factors in selecting the number of poles

  1. Frequency: f=Pn/2f = Pn/2 should usually be 25–50 Hz. More poles raise frequency and iron loss in the armature.
  2. Weight of iron: flux per pole falls as PP increases, so the yoke and armature core become thinner; iron weight falls.
  3. Weight of copper: armature end connections are shorter with smaller pole pitch, so armature copper falls; field copper changes little.
  4. Armature reaction: armature AT per pole =ac πD/2P= ac\,\pi D/2P falls with more poles, reducing distortion and the extra field mmf needed.
  5. Current per brush arm: for a lap winding the current per path (Ia/PI_a/P) should not exceed about 200 A; large-current machines need more poles.
  6. Commutator length: more poles give more brush arms with less current each, so a shorter commutator.
  7. Labour and cost: more poles mean more field coils and parts, so more labour.
  8. Flashover: voltage between brush arms and the voltage between segments must stay within safe limits.

So the number of poles is chosen as a compromise. Usual choices: 2 poles up to about 5 kW, 4 poles for about 5–100 kW, and 6 or more for larger machines.

✓ Answer checked by Claude Sonnet 5.5

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