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BLDC motor torque equation and characteristics

Short answer

With two phases conducting in series, line emf is E = 4NBlr ω = ke ω. Power P = EI = ke ω I, so electromagnetic torque T = P/ω = ke I = kt I. The torque-speed curve is a straight drooping line from no-load speed ω0=V/ke to stall torque Tstall=ktV/R, with continuous and intermittent operating zones.

Derive the torque equation of permanent magnet BLDC motor. And also explain torque-speed characteristics of the same motor.

A permanent-magnet BLDC motor has magnets on the rotor and a 3-phase stator winding switched electronically; with trapezoidal (120° conduction) drive, two phases conduct at a time in series.

Torque equation

Each conductor of length ll at radius rr in a gap flux density BB has emf e=Blv=Blrωe = Blv = Blr\omega. With NN turns (2N2N conductors) per phase:

Eph=2NBlr ωEline=2Eph=4NBlr ω=ke ω(two phases in series)P=ElineI=4NBlr ωIT=Pω=4NBlr I=ktI\begin{aligned} E_{ph} &= 2NBlr\,\omega \\ E_{line} &= 2E_{ph} = 4NBlr\,\omega = k_e\,\omega \quad (\text{two phases in series}) \\ P &= E_{line} I = 4NBlr\,\omega I \\ T &= \frac{P}{\omega} = 4NBlr\,I = k_t I \end{aligned}

Torque is proportional to current, and kt=kek_t = k_e in SI units, as in a PM DC motor.

Torque–speed characteristic

From V=E+IR=keω+R TktV = E + IR = k_e\omega + \dfrac{R\,T}{k_t}:

ω=Vke−RkektT\omega = \frac{V}{k_e} - \frac{R}{k_e k_t}T
 speed
  ^ w0 = V/ke (no load)
  |\
  |  \   continuous | intermittent
  |    \   zone     |    zone
  |      \          |
  +--------\--------+----> T
                 stall T = kt V / R
  • Straight drooping line: speed falls slightly as torque rises (like a shunt DC motor).
  • Rated operation lies in the continuous zone; the intermittent zone (up to about 2× rated torque) is limited by heating.

✓ Answer checked by Claude Sonnet 5.5

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