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S-curve 3-h UH and flood from two storms

Short answer

Derive3-h UH via S-curve: peak180 m³/s at8 h. Effective rain after φ=0.3 cm/h:7.1 cm over3 h, then6.4 cm over2 h. Flood hydrograph with baseflow10 m³/s peaks at2384 m³/s at10 h.

The ordinates of a 2-h UH are given below. Derive the ordinates of a 3-h UH by S-curve method.

Time (hr)024681012141618202224
Ordinates of 2-h UH (m3^3/s)0251001601901701107030201560

Calculate the flood discharge of a storm of 3 h and 2 h rainfall of 8 cm and 7 cm respectively. Consider ϕ\phi-index 0.3 cm/hr and baseflow 10 m3^3/s.

Part 1: 3-h UH from the 2-h UH by the S-curve method

S(t)=U2(t)+S(t−2)S(t)=U_2(t)+S(t-2), and U3(t)=23[S(t)−S(t−3)]U_3(t)=\dfrac{2}{3}\left[S(t)-S(t-3)\right] with S(t−3)S(t-3) interpolated linearly.

t (h)U2U_2S(t)S(t)S(t−3)S(t-3)U3U_3 (m3^3/s)
00000.00
22525016.67
410012512.575.00
616028575140.00
8190475205180.00
10170645380176.67
12110755560130.00
147082570083.33
163085579043.33
182087584023.33
201589086516.67
226896882.59.00
2408968932.00

The S-curve reaches equilibrium (896 m3^3/s) at 22 h.

Part 2: Flood hydrograph

Effective rainfall (ϕ\phi = 0.3 cm/h, assumed consecutive storms: 3 h of 8 cm, then 2 h of 7 cm):

  • 3-h storm: 8−0.3×3=7.18 - 0.3\times3 = 7.1 cm
  • 2-h storm: 7−0.3×2=6.47 - 0.3\times2 = 6.4 cm, starting at t = 3 h.
Q(t)=10+7.1 U3(t)+6.4 U2(t−3)Q(t)=10+7.1\,U_3(t)+6.4\,U_2(t-3)

U3U_3 and U2U_2 are read at hourly intervals (linear interpolation of the S-curve; U2(t)=S(t)−S(t−2)U_2(t)=S(t)-S(t-2)).

t (h)U3(t)U_3(t)U2(t−3)U_2(t-3)7.1 U3U_36.4 U2U_2Q (m3^3/s)
00.00.00.00.010.0
18.30.059.20.069.2
216.70.0118.30.0128.3
350.00.0355.00.0365.0
475.012.5532.580.0622.5
5120.025.0852.0160.01022.0
6140.062.5994.0400.01404.0
7170.0100.01207.0640.01857.0
8180.0130.01278.0832.02120.0
9183.3160.01301.71024.02335.7
10176.7175.01254.31120.02384.3
11150.0190.01065.01216.02291.0
12130.0180.0923.01152.02085.0
1396.7170.0686.31088.01784.3
1483.3140.0591.7896.01497.7
1556.7110.0402.3704.01116.3
1643.390.0307.7576.0893.7
1726.770.0189.3448.0647.3
1823.350.0165.7320.0495.7
1918.330.0130.2192.0332.2
2016.725.0118.3160.0288.3
2112.020.085.2128.0223.2
229.017.563.9112.0185.9
234.015.028.496.0134.4
242.010.514.267.291.4
250.06.00.038.448.4
260.03.00.019.229.2
270.00.00.00.010.0

Answer: The 3-h UH ordinates are 0, 16.7, 75, 140, 180, 176.7, 130, 83.3, 43.3, 23.3, 16.7, 9, 2 m3^3/s at 0, 2, ..., 24 h. The flood hydrograph peaks at about 2384 m3^3/s at 10 h and returns to the base flow of 10 m3^3/s by about 27 h.

✓ Answer checked by Claude Sonnet 5.5

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