- 2074 Asoj · 1+3+4 marks
Band pass (ω1 = 100, ω2 = 10000) from normalized ladder
Short answer
Given ω₁=100 rad/s, ω₂=10000 rad/s, ω₀=1000 rad/s, B=9900 rad/s. Transform the normalized ladder: series 0.7654 H → 77.313 µH series with 12.934 mF; shunt 1.8485 F → 186.72 µF parallel with 5.3557 mH; series 1.8485 H → 186.72 µH series with 5.3557 mF; shunt 0.7654 F → 77.313 µF parallel with 12.934 mH. All sections resonate at 1000 rad/s, passband 100–10000 rad/s.
What is frequency transformation in filter design? How can you obtain a bandpass filter from given lowpass filter at normalized frequency? Obtain a bandpass filter having ω1 = 100 rad/s and ω2 = 10000 rad/s from following lowpass filter at normalized frequency. [Figure: source V1, 1 Ω source resistor, series 0.7654 H, shunt 1.8485 F, series 1.8485 H, shunt 0.7654 F, 1 Ω load (output V2)]
Frequency transformation
Frequency transformation is a change of the complex frequency variable that converts a normalized low-pass prototype filter (cutoff 1 rad/s) into a high-pass, band-pass or band-stop filter (or a low-pass with a different cutoff). The magnitude response of the prototype is mapped onto the new frequency axis, so the same attenuation values appear at the corresponding new frequencies.
Obtaining a band-pass filter from the normalized low-pass filter
Replace by , where and . Applied to each element:
- series → series with ;
- shunt → parallel with ;
- resistors unchanged.
This maps and of the low-pass prototype, so the LP passband becomes the band to .
Design for rad/s, rad/s
Given ladder (4th-order Butterworth, 1 Ω terminations): series 0.7654 H, shunt 1.8485 F, series 1.8485 H, shunt 0.7654 F.
Rs=1 [ Z1 ] [ Z3 ]
o-/\/\-[ ]--+-----[ ]--+------+---o
| | | | +
Vs [ Y2 ] [ Y4 ] RL=1 Vo
| | | | -
o--------------+-------------+------+---o
| Arm | Prototype | Band-pass element |
|---|---|---|
| Z1 | 0.7654 H | 77.313 μH in series with 12.934 mF |
| Y2 | 1.8485 F | 186.72 μF ∥ 5.3557 mH |
| Z3 | 1.8485 H | 186.72 μH in series with 5.3557 mF |
| Y4 | 0.7654 F | 77.313 μF ∥ 12.934 mH |
Check: rad/s. These values are for terminations. For practical values, magnitude-scale by (e.g. for 1 kΩ terminations): multiply every L by and divide every C by .
✓ Answer checked by Claude Sonnet 5.5
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