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- 2082 Baisakh · 1+4 marks
Ideal gyrator and floating inductor simulation
Short answer
An ideal gyrator is a lossless two-port with Zin = r^2/ZL. A floating inductor is realized by cascading two identical gyrators with a grounded capacitor between them, yielding L = r^2 C.
What is ideal gyrator? How can you simulate floating inductor using gyrator? Explain with necessary figure and derivations.
Ideal gyrator
An ideal gyrator is a lossless two-port that inverts impedance: a load on port 2 appears at port 1 as , where is the gyration resistance. Its defining equations are
So a capacitor on port 2 gives with . A gyrator is built with op-amps (e.g. two voltage-controlled current sources of opposite sign, , , ).
Floating inductor using gyrators
One gyrator with a grounded capacitor gives only a grounded inductor. A floating inductor is made by cascading two identical gyrators with a grounded capacitor between them:
+-----------+ +-----------+
a o----| Gyrator 1 |----+-----| Gyrator 2 |----o b
| (r) | | | (r) |
+-----------+ === C +-----------+
|
GND ---------------------------------------------- GND
Each gyrator and the capacitor share the common ground. The transmission (ABCD) matrix of an ideal gyrator (, , with leaving port 2) and of a shunt capacitor are
For the cascade:
The matrix is that of a single series impedance between the two terminals. Here , so the circuit between a and b is a floating inductor
Example: = 10 kΩ and = 10 nF give = 1 H. The two gyrators must have equal gyration resistance; any mismatch leaves an unwanted grounded element. The capacitor is grounded, which suits IC realisation.
✓ Answer checked by Claude Sonnet 5.5
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