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- 2080 Baisakh · 3+2+3 marks
RC impedance properties; Foster form
Short answer
RC impedance: poles and zeros on negative real axis, simple, alternating; lowest is a pole, highest a zero; Z(0)>Z(∞). Valid: Z(s)=(s+3)(s+6)/((s+1)(s+5)). Foster I: series 1 Ω, then parallel branches R=2.5 Ω, C=0.4 F and R=0.1 Ω, C=2 F.
What are the properties of RC driving point impedance function? Which of the following functions are valid RC driving point impedance function and why? Z(s) = (s+3)(s+6)/((s+1)(s+5)); Z(s) = 2(s+1)(s+3)/((s+2)(s+4)). Find Foster form of valid RC driving point impedance function.
Properties of RC driving-point impedance
An RC driving-point impedance has these properties:
- All poles and zeros are simple and lie on the negative real axis of the -plane (including the origin).
- Poles and zeros alternate along the negative real axis.
- The critical frequency nearest the origin (lowest) is a pole; it may be at .
- The critical frequency farthest from the origin is a zero; it may be at .
- , and is a constant (no pole at infinity).
- Residues of at its poles are real and positive; on the real axis .
- The same form describes an RL admittance .
Checking the functions
| Function | Critical frequencies | Result |
|---|---|---|
| (a) | p 1, z 3, p 5, z 6 | Lowest is a pole, highest a zero, alternate; → valid RC |
| (b) | z 1, p 2, z 3, p 4 | Lowest critical frequency is a zero and → not RC impedance (it is an RL impedance / RC admittance) |
Foster form of (a)
Foster-I (series) form: Expand in partial fractions; every residue must be positive:
| Term | Rule | Element value |
|---|---|---|
| (series) | 1 Ω | |
| (pole at ) | , | = 5/2 Ω (≈ 2.5 Ω), = 2/5 F (≈ 0.4 F) |
| (pole at ) | , | = 1/10 Ω (≈ 0.1 Ω), = 2 F |
o--[R1]--[R2||C2]--[R3||C3]--o
Foster-II (parallel) form: Take . Expand in partial fractions and multiply back by :
| Term | Rule | Element value |
|---|---|---|
| (shunt) | 18/5 Ω (≈ 3.6 Ω) | |
| – in series (pole at ) | , | = 9/4 Ω (≈ 2.25 Ω), = 4/27 F (≈ 0.1481 F) |
| – in series (pole at ) | , | = 18/5 Ω (≈ 3.6 Ω), = 5/108 F (≈ 0.0463 F) |
o--+-------+-------+
| | |
[R1] [R2] [R3]
| [C2] [C3]
| | |
o--+-------+-------+
✓ Answer checked by Claude Sonnet 5.5
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