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SC equivalents: inverting summer, lossy and non-inverting integrators

Short answer

A switched capacitor filter replaces resistors with capacitors and MOS switches, using a two-phase clock. Applications include voice-band filters, modems, programmable filters, and mixed-signal ICs. The inverting summer gives V_o = -(C1/C_F V1 + C2/C_F V2). The lossy integrator has T(s) = -(f_c C1/C_F)/(s + f_c C2/C_F). The non-inverting integrator yields T(s) = +f_c C1/(s C_F).

What is switched capacitor filter? What are its applications? Draw the switched capacitor equivalent circuit for inverting summer, lossy integrator and non-inverting integrator.

Switched capacitor filter

A switched capacitor (SC) filter is an active filter in which every resistor of an active-RC filter is replaced by a capacitor and MOS switches driven by a two-phase non-overlapping clock. The switched capacitor behaves like a resistor R=1/(fcC)R = 1/(f_cC), so the filter needs only op-amps, capacitors and switches, all easily built on one MOS chip.

Applications

  • Voice-band filters in telephone systems (PCM codec anti-aliasing and reconstruction filters, DTMF tone decoders).
  • Modems, audio equalizers and speech processing ICs.
  • Clock-tunable (programmable) filters: changing fcf_c shifts all frequencies, e.g. MF10, MAX7400 type ICs.
  • Mixed-signal ICs: sigma-delta ADCs, sample-and-hold, data acquisition and biomedical front ends.

SC equivalent circuits

SC resistor. A capacitor CC switched between nodes 1 and 2 by non-overlapping clocks transfers Δq=C(V1−V2)\Delta q = C(V_1 - V_2) each period TcT_c, so I=fcC(V1−V2)I = f_cC(V_1 - V_2) and Req=1/(fcC)R_{eq} = 1/(f_cC).

       phi1          phi2
 V1 ----o/o----+----o/o---- V2
               |
              ===  CR
               |
              GND

Inverting summer. The active-RC summer gives Vo=−(RFR1V1+RFR2V2)V_o = -\left(\frac{R_F}{R_1}V_1 + \frac{R_F}{R_2}V_2\right). Replacing each resistor by a switched capacitor (R=1/(fcC)R = 1/(f_cC)) gives RF/Ri=Ci/CFR_F/R_i = C_i/C_F, so

Vo=−(C1CFV1+C2CFV2)V_o = -\left(\frac{C_1}{C_F}V_1 + \frac{C_2}{C_F}V_2\right)
              +--[CF-SC]---+
              |            |
 V1 -[C1-SC]--+   |\       |
              +---|-\      |
 V2 -[C2-SC]--+   |  >-----+---> Vo
               +--|+/
               |  |/
              GND

The gains depend only on capacitor ratios.

Inverting lossy (damped) integrator. Active-RC form: input resistor R1R_1, feedback R2∥CFR_2 \parallel C_F:

T(s)=−1/(R1CF)s+1/(R2CF)T(s) = -\frac{1/(R_1C_F)}{s + 1/(R_2C_F)}

Replacing R1R_1 and R2R_2 by switched capacitors C1C_1 and C2C_2 (1/R=fcC1/R = f_cC):

T(s)=−fcC1/CFs+fcC2/CFT(s) = -\frac{f_cC_1/C_F}{s + f_cC_2/C_F}
                    CF
              +-----||-----+
              |            |
              +--[C2-SC]---+
              |            |
              |   |\       |
 Vi -[C1-SC]--+---|-\      |
                  |  >-----+---> Vo
               +--|+/
               |  |/
              GND

DC gain =−C1/C2= -C_1/C_2 and pole ωp=fcC2/CF\omega_p = f_cC_2/C_F, both set by capacitor ratios. It is the first-order low-pass section used in SC ladders and biquads.

Non-inverting integrator. Here the switched capacitor is connected so that its charge is reversed before it reaches the op-amp: during ϕ1\phi_1, C1C_1 is charged to ViV_i (top plate to ViV_i, bottom plate to ground); during ϕ2\phi_2, the top plate is grounded and the bottom plate is connected to the virtual ground. Charge −C1Vi-C_1V_i is pushed into CFC_F, so the switched capacitor acts as a negative resistor R=−1/(fcC1)R = -1/(f_cC_1):

T(s)=VoVi=+fcC1sCFT(s) = \frac{V_o}{V_i} = +\frac{f_cC_1}{sC_F}
       phi1   C1   phi2           CF
 Vi ---o/o--+-||-+--o/o--+    +---||---+
            |    |       |    |        |
  GND -o/o--+    +-o/o-  +----+  |\    |
       phi2        | phi1     +--|-\   |
                  GND            |  >--+--> Vo
                              +--|+/
                              |  |/
                             GND

(Left plate: ViV_i on ϕ1\phi_1, ground on ϕ2\phi_2; right plate: ground on ϕ1\phi_1, op-amp input on ϕ2\phi_2.) In the z-domain: H(z)=+C1CF⋅z−11−z−1H(z) = +\frac{C_1}{C_F}\cdot\frac{z^{-1}}{1 - z^{-1}}. A non-inverting integrator removes the need for an extra inverter in biquads, which is a big advantage of SC over active-RC.

✓ Answer checked by Claude Sonnet 5.5

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