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SC applications; summer and integrators

Short answer

A switched capacitor filter uses capacitors and switches to simulate resistors, enabling monolithic integration. Applications: telephone codecs, modems, tunable filters, sigma‑delta converters. Inverting summer: Vo = -Σ(Ci/CF)Vi. Inverting integrator: H(s) = -(fc C1)/(s CF). Non-inverting integrator: by reversing charge, H(s) = +(fc C1)/(s CF).

What is switched capacitor filter? What are the applications of switched capacitor? How summer, inverting integrator and non-inverting integrator can be realized using switched capacitor? Explain with necessary diagrams and transfer function.

Switched capacitor filter

A switched capacitor (SC) filter is an active filter in which every resistor of an active-RC filter is replaced by a capacitor and MOS switches driven by a two-phase non-overlapping clock. The switched capacitor behaves like a resistor R=1/(fcC)R = 1/(f_cC), so the filter needs only op-amps, capacitors and switches, all easily built on one MOS chip.

Applications

  • Voice-band filters in telephone systems (PCM codec anti-aliasing and reconstruction filters, DTMF tone decoders).
  • Modems, audio equalizers and speech processing ICs.
  • Clock-tunable (programmable) filters: changing fcf_c shifts all frequencies, e.g. MF10, MAX7400 type ICs.
  • Mixed-signal ICs: sigma-delta ADCs, sample-and-hold, data acquisition and biomedical front ends.

Realization of summer and integrators

Basis: a capacitor CC switched at fcf_c acts as R=1/(fcC)R = 1/(f_cC) (charge C(V1−V2)C(V_1 - V_2) moved per period). So each resistor of an active-RC circuit is replaced by a switched capacitor.

Inverting summer. The active-RC summer gives Vo=−(RFR1V1+RFR2V2)V_o = -\left(\frac{R_F}{R_1}V_1 + \frac{R_F}{R_2}V_2\right). Replacing each resistor by a switched capacitor (R=1/(fcC)R = 1/(f_cC)) gives RF/Ri=Ci/CFR_F/R_i = C_i/C_F, so

Vo=−(C1CFV1+C2CFV2)V_o = -\left(\frac{C_1}{C_F}V_1 + \frac{C_2}{C_F}V_2\right)
              +--[CF-SC]---+
              |            |
 V1 -[C1-SC]--+   |\       |
              +---|-\      |
 V2 -[C2-SC]--+   |  >-----+---> Vo
               +--|+/
               |  |/
              GND

The gains depend only on capacitor ratios.

Inverting integrator. The active-RC integrator has T(s)=−1sRCFT(s) = -\frac{1}{sRC_F}. Replacing RR by a switched capacitor C1C_1:

T(s)=VoVi=−fcC1sCF=−1s⋅C1CFfcT(s) = \frac{V_o}{V_i} = -\frac{f_cC_1}{sC_F} = -\frac{1}{s}\cdot\frac{C_1}{C_F}f_c
                    CF
              +-----||-----+
       phi1   |  phi2      |
 Vi ---o/o--+-o/o-+  |\    |
            |     +--|-\   |
           ===C1     |  >--+---> Vo
            |     +--|+/
           GND    |  |/
                 GND

The integrator time constant CF/(fcC1)C_F/(f_cC_1) is set by a capacitor ratio. (In the z-domain, the stray-insensitive version gives H(z)=−C1CF⋅11−z−1H(z) = -\frac{C_1}{C_F}\cdot\frac{1}{1 - z^{-1}}.)

Non-inverting integrator. Here the switched capacitor is connected so that its charge is reversed before it reaches the op-amp: during ϕ1\phi_1, C1C_1 is charged to ViV_i (top plate to ViV_i, bottom plate to ground); during ϕ2\phi_2, the top plate is grounded and the bottom plate is connected to the virtual ground. Charge −C1Vi-C_1V_i is pushed into CFC_F, so the switched capacitor acts as a negative resistor R=−1/(fcC1)R = -1/(f_cC_1):

T(s)=VoVi=+fcC1sCFT(s) = \frac{V_o}{V_i} = +\frac{f_cC_1}{sC_F}
       phi1   C1   phi2           CF
 Vi ---o/o--+-||-+--o/o--+    +---||---+
            |    |       |    |        |
  GND -o/o--+    +-o/o-  +----+  |\    |
       phi2        | phi1     +--|-\   |
                  GND            |  >--+--> Vo
                              +--|+/
                              |  |/
                             GND

(Left plate: ViV_i on ϕ1\phi_1, ground on ϕ2\phi_2; right plate: ground on ϕ1\phi_1, op-amp input on ϕ2\phi_2.) In the z-domain: H(z)=+C1CF⋅z−11−z−1H(z) = +\frac{C_1}{C_F}\cdot\frac{z^{-1}}{1 - z^{-1}}. A non-inverting integrator removes the need for an extra inverter in biquads, which is a big advantage of SC over active-RC.

✓ Answer checked by Claude Sonnet 5.5

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