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Steam nozzles and critical pressure ratio

Short answer

Steam nozzles expand steam to produce high-velocity jets; used in turbines, injectors. Types: convergent, convergent-divergent. Velocity from steady flow energy: V2 = √(2(h1-h2)). Mass flow rate maximizes at critical pressure ratio: 0.546 for superheated steam (n=1.3), 0.577 for dry saturated (n=1.135).

What are steam nozzles? Name their types and applications. Using the steady flow energy equation derive an expression for the velocity of steam at nozzle exit, and show that the discharge is maximum at the critical pressure. Give the critical pressure ratio for superheated and dry saturated steam.

A steam nozzle is a passage of varying cross-section that converts the heat (enthalpy) energy of steam into kinetic energy by expansion from a high to a low pressure. Its main use is in steam turbines (to produce jets), and also in steam injectors, ejectors, and jet condensers.

Types

TypeShapeUse
ConvergentArea decreases to exitPressure ratio above critical; some reaction blading
DivergentArea increasesRarely used alone
Convergent-divergent (De Laval)Converging to throat, then divergingImpulse turbines with large pressure ratio

Also, nozzles may be classified by cross-section (circular, rectangular) and by arrangement (single, ring).

Exit velocity (steady flow energy equation)

For adiabatic flow with no work, negligible change in height, the SFEE between inlet (1) and exit (2) is

h1+V122=h2+V222h_1+\frac{V_1^2}{2}=h_2+\frac{V_2^2}{2}

Neglecting inlet velocity (V1≈0V_1\approx0):

V2=2(h1−h2)  m/s,  h in J/kgV_2=\sqrt{2(h_1-h_2)}\ \ \text{m/s},\ \ h\text{ in J/kg}

(or V2=44.72h1−h2V_2=44.72\sqrt{h_1-h_2} with hh in kJ/kg). For an isentropic expansion with pvn=constantpv^n=\text{constant} (n=1.3n=1.3 for superheated, 1.135 for dry saturated steam, Zeuner's law), h1−h2=nn−1(p1v1−p2v2)h_1-h_2=\dfrac{n}{n-1}(p_1v_1-p_2v_2), so

V2=2nn−1 p1v1[1−(p2p1)n−1n]V_2=\sqrt{\frac{2n}{n-1}\,p_1v_1\left[1-\left(\frac{p_2}{p_1}\right)^{\frac{n-1}{n}}\right]}

Mass flow and maximum discharge

Mass flow per unit exit area, using v2=v1(p1/p2)1/nv_2=v_1(p_1/p_2)^{1/n}:

mA=V2v2=2nn−1p1v1[(p2p1)2n−(p2p1)n+1n]\frac{m}{A}=\frac{V_2}{v_2}=\sqrt{\frac{2n}{n-1}\frac{p_1}{v_1}\left[\left(\frac{p_2}{p_1}\right)^{\frac{2}{n}}-\left(\frac{p_2}{p_1}\right)^{\frac{n+1}{n}}\right]}

Let r=p2/p1r=p_2/p_1. The flow per unit area is a maximum when d(m/A)/dr=0d(m/A)/dr=0, i.e. when the bracket is a maximum:

2nr2n−1−n+1nr1n=0 ⇒ r=(2n+1)nn−1\frac{2}{n}r^{\frac{2}{n}-1}-\frac{n+1}{n}r^{\frac{1}{n}}=0\ \Rightarrow\ r=\left(\frac{2}{n+1}\right)^{\frac{n}{n-1}}

This is the critical pressure ratio pc/p1p_c/p_1, reached at the throat. At it, the velocity at the throat equals the local velocity of sound, and the nozzle is "choked": lowering the back pressure further cannot increase the mass flow through a convergent nozzle.

SteamnnCritical pressure ratio pc/p1p_c/p_1
Superheated1.3(2/2.3)1.3/0.3=0.546(2/2.3)^{1.3/0.3}=0.546
Dry saturated1.135(2/2.135)1.135/0.135=0.577(2/2.135)^{1.135/0.135}=0.577

Throat velocity: Vt=2nn+1p1v1V_t=\sqrt{\dfrac{2n}{n+1}p_1v_1}.

Use of the result: if the back pressure is above pcp_c, a simple convergent nozzle is used, and the exit pressure equals the back pressure. If the back pressure is below pcp_c, a convergent-divergent nozzle is required to expand the steam fully to the back pressure, with a supersonic jet in the divergent part.

✓ Answer checked by Claude Sonnet 5.5

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