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Fully compensated raft and its depth

Short answer

A fully compensated raft is placed at depth such that excavated soil weight equals total structure weight, net pressure zero, preventing settlement. From equilibrium: Q/A = γ D_f, thus D_f = Q/(γ A).

Define fully compensated raft foundation. Also derive the relation to calculate its depth.

Fully compensated raft: a raft placed at such depth that the weight of the soil excavated is equal to the total weight of the structure, including the raft. The net pressure on the soil is then zero, and, in principle, no extra settlement or shear failure occurs.

Derivation of depth

Let QQ = total load of the structure (including the raft), AA = area of the raft, γ\gamma = unit weight of the excavated soil, DfD_f = depth of the raft.

Gross pressure at foundation level: q=QAq = \dfrac{Q}{A}

Weight of soil removed per unit area (overburden pressure): γDf\gamma D_f

Net pressure on the soil: qnet=QA−γDfq_{net} = \dfrac{Q}{A} - \gamma D_f

For a fully compensated raft qnet=0q_{net} = 0:

QA=γDf\frac{Q}{A} = \gamma D_f Df=QγA=qγD_f = \frac{Q}{\gamma A} = \frac{q}{\gamma}

If the water table is above the raft, the buoyancy reduces the soil weight, so γDf\gamma D_f is replaced by the vertical effective stress at base, or the buoyant uplift is subtracted from QQ.

✓ Answer checked by Claude Sonnet 5.5

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