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Stability of cantilever wall, q = 50 kPa

Short answer

Overturning safety factor is 3.01, sliding safety factor 1.60. Maximum base pressure 173.3 kN/m² is below the allowable 600 kN/m², and eccentricity 0.29 m is within B/6; the wall is stable.

Check the overall stability of the cantilever retaining wall shown in figure below. Take the allowable soil pressure as 600 kN/m2600\ \text{kN/m}^2. [Figure: cantilever wall, surcharge 50 kPa on backfill, stem top width 0.30 m, backfill height 4.00 m, backfill γ1=18 kN/m3\gamma_1 = 18\ \text{kN/m}^3, ϕ=40∘\phi = 40^\circ, δ=25∘\delta = 25^\circ; heel 1.90 m, base slab thickness 0.45 m, total base width 2.80 m, embedment (toe side) 1.00 m. Dimensions as read from the scan.]

Assumptions (dimensions read from the scan): stem 4.00 m high and 0.30 m thick, base slab 0.45 m thick (total height 4.45 m), base width 2.80 m, heel 1.90 m so toe =2.80−1.90−0.30=0.60= 2.80-1.90-0.30 = 0.60 m; embedment 1.0 m (soil over the toe is 0.55 m high). Soil γ=18\gamma = 18 kN/m3^3, ϕ=40∘\phi = 40^\circ, concrete 25 kN/m3^3, base friction δ=25∘\delta = 25^\circ, surcharge 50 kPa. Rankine active pressure on a vertical plane through the heel.

1. Active thrust

Ka=tan⁡2(45∘−20∘)=0.2174K_a = \tan^2(45^\circ-20^\circ) = 0.2174
PartForce (kN/m)Arm above base (m)Moment
Surcharge KaqHK_a qH = 0.2174 x 50 x 4.4548.382.225107.65
Soil 12KaγH2\tfrac12K_a\gamma H^238.751.48357.48
Total87.13165.13

2. Vertical loads (about the toe)

PartForce (kN/m)Arm (m)Moment
Stem 0.3 x 4 x 2530.000.75022.50
Base slab 2.8 x 0.45 x 2531.501.40044.10
Soil on heel 1.9 x 4 x 18136.801.850253.08
Surcharge on heel 50 x 1.995.001.850175.75
Soil on toe 0.6 x 0.55 x 185.940.3001.78
Total299.24497.21

3. Checks

  • Overturning: FSot=497.21/165.13=3.01FS_{ot} = 497.21/165.13 = 3.01 (>2, safe).
  • Sliding: FSs=299.24tan⁡25∘/87.13=1.60FS_s = 299.24\tan25^\circ/87.13 = 1.60 (>1.5, safe even without passive resistance; with the passive force on the 1 m embedment, Pp=12KpγD2=41.4P_p = \tfrac12K_p\gamma D^2 = 41.4 kN/m, it rises to 2.08).
  • Base pressure: xˉ=(497.21−165.13)/299.24=1.110\bar x = (497.21-165.13)/299.24 = 1.110 m, e=1.4−1.110=0.290e = 1.4-1.110 = 0.290 m <B/6=0.467< B/6 = 0.467 m, so the whole base is in compression.
qmax=173.3 kN/m2,qmin=40.4 kN/m2q_{max} = 173.3\ \text{kN/m}^2,\qquad q_{min} = 40.4\ \text{kN/m}^2

qmax<qa=600q_{max} < q_a = 600 kN/m2^2. Safe.

Answer: the wall is stable. FSot=3.01FS_{ot} = 3.01, FSsliding=1.60FS_{sliding} = 1.60, qmax=173.3q_{max} = 173.3 kN/m2^2 <600<600 kN/m2^2, e<B/6e < B/6.

✓ Answer checked by Claude Sonnet 5.5

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