- 2074 Asoj · 6 marks
Population, parameter, statistic; samples of 3,7,11,15
Short answer
Population is the complete set under study; a parameter is a numerical measure of the population, and a statistic is a numerical measure from a sample. For 3,7,11,15 with samples of size 2 without replacement, population mean μ=9 and SE=(4.4721/√2)√(2/3)=2.5820.
Define population. Sample parameter and statistic with suitable examples. A population consists of 3, 7, 11, 15. Consider all possible samples of size two which can be drawn without replacement from this population. Find population mean and Standard error of mean.
Definitions
- Population: the complete collection of all individuals or items under study, for example all 2000 IOE students of a campus.
- Sample: a part of the population selected for study, for example 100 of those students.
- Parameter: a numerical measure of a population, such as the population mean μ, standard deviation σ or proportion P. It is fixed (usually unknown).
- Statistic: a numerical measure computed from a sample, such as the sample mean x̄, standard deviation s or proportion p̂. It varies from sample to sample.
Example: the average marks of all 2000 students is a parameter (μ); the average of the 100 sampled students is a statistic (x̄).
Numerical
Population: 3, 7, 11, 15 (N = 4), n = 2 without replacement, 6 samples.
Population mean and standard deviation
μ = Σx/N = 36/4 = 9
σ² = Σ(x − μ)²/N = (36 + 4 + 4 + 36)/4 = 80/4 = 20
σ = √20 = 4.4721
All samples
| No. | Sample | Sample mean |
|---|---|---|
| 1 | (3, 7) | 5 |
| 2 | (3, 11) | 7 |
| 3 | (3, 15) | 9 |
| 4 | (7, 11) | 9 |
| 5 | (7, 15) | 11 |
| 6 | (11, 15) | 13 |
Sum of sample means = 5 + 7 + 9 + 9 + 11 + 13 = 54
Mean of sample means = 54/6 = 9
(equal to μ = 9).
Standard error of the mean
With sampling without replacement from a finite population:
SE = (σ/√n) × √((N − n)/(N − 1)) = (4.4721/√2) × √((4 − 2)/(4 − 1))
= 3.1623 × 0.8165 = 2.5820
(Direct check: the standard deviation of the 6 sample means is 2.5820.)
Answer: population mean = 9; standard error of the mean = 2.5820.
✓ Answer checked by Claude Sonnet 5.5
Related questions
- Samples of 2,8,14,20 with standard error · Probability and Statistics, chapter 4 · asked 2×
- Standard error; population 12,19,13,16 · Probability and Statistics, chapter 4
- Sampling distribution: population 5,6,9,12 · Probability and Statistics, chapter 4
- Sampling distribution: population 4,8,12,16,20 · Probability and Statistics, chapter 4
- Sampling distribution of proportion; parameter vs statistic · Probability and Statistics, chapter 4
- Sample survey advantages; sample size for bills · Probability and Statistics, chapter 6
- K-map Π(0,4,5,8,9,11,15), standard SOP · Digital Logic, chapter 3 · asked 2×
- K-map Σ(0,1,4,8,10,11,12)+d, standard minterm · Digital Logic, chapter 3
- Capacitor size, four-node 11 kV feeder · Transmission and Distribution System Design, chapter 7 · asked 5×
- Drained and CU tests on two samples · Soil Mechanics, chapter 10