- 2071 Chaitra · 15 marks
Consistent deformation: frame, BMD, SFD, normal thrust
Short answer
Releasing hinge at D, choosing H_D and V_D as redundants, consistent deformation gives H_D = 3.09 kN (left) and V_D = 10.84 kN (up). Fixed-end reactions: H_A = 26.91 kN (left), V_A = 4.16 kN (up), M_A = 31.63 kNm (anticlockwise).
Using the consistent deformation method analyse the frame shown in figure and draw bending moment, shear force and normal thrust diagram. [Figure: frame; left column 2EI with 10 kN/m UDL horizontally, height 3 m + 1 m...; beam EI of 2 m + 2 m with 15 kN downward at mid-span; right column 2EI.]
Reading of the figure (as assumed): portal frame of height 4 m and span 4 m. The left column AB () is fixed at A and carries a horizontal UDL of 10 kN/m over its lower 3 m (towards the right); the beam BC (, 2 m + 2 m) carries 15 kN downward at mid-span F; the right column CD () is hinged at D.
, so . By the consistent deformation method, release the hinge at D and take the reactions (horizontal, ) and (vertical, ) at D as redundants. The displacements of D in the primary structure must be cancelled by the redundants, that is, the total displacement at D along each redundant is zero.
B ----F---- C
| 15 kN |
10-> | 4 m
kN/m |
| o D
A (fixed)
Consistent deformation equations
where (displacements of D in the primary structure) and .
Final bending moments (kNm, + tension on the inside)
| Section | ||||
|---|---|---|---|---|
| A | -75.00 | 0.00 | 4.00 | -31.63 |
| Q (top of UDL) | -30.00 | 3.00 | 4.00 | 4.10 |
| B | -30.00 | 4.00 | 4.00 | 1.01 |
| F (load) | 0.00 | 4.00 | 2.00 | 9.33 |
| C | 0.00 | 4.00 | 0.00 | -12.35 |
| D | 0.00 | 0.00 | 0.00 | 0.00 |
Shear force (kN)
| Member | At lower end | At upper end |
|---|---|---|
| AQ (UDL zone) | +26.91 | -3.09 |
| QB | -3.09 | -3.09 |
| BF | +4.16 | +4.16 |
| FC | -10.84 | -10.84 |
| CD | +3.09 | +3.09 |
(Column shears are horizontal forces; positive means towards the right on the left face.)
Normal thrust (kN, compression negative)
| Member | Axial force |
|---|---|
| AB (left column) | -4.16 |
| BC (beam) | -3.09 |
| CD (right column) | -10.84 |
Reactions
- D (hinge): kN (towards the left), kN ()
- A (fixed): kN (towards the left), kN (), kNm (anticlockwise)
Check: : (UDL resultant kN); : kN.
Answer: kN, kN; kN, kN, kNm. The BMD, SFD and thrust values are tabulated above.
✓ Answer checked by Claude Opus 5.5 (high effort)
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