- 2072 Kartik · 15 marks
Moment distribution: frame, 150 kN, 60 kN/m
Analyse the frame shown in figure below by using the moment distribution method. [Figure: frame; column AB (2I) of 10 m (8 m + 2 m marks), A fixed; 150 kN horizontal at B; beam B-C-D with 50 kN loads at 2 m from B and at 4 m, spans 2 m + 4 m + 2 m; BC (2I) and C-D (I) of 5 m with 60 kN/m UDL, D roller; column CE (I) of 6 m, E fixed.]
Assumptions (figure partly illegible): column AB (2I) is 10 m high, fixed at A; the girder is B-C-D with BC = 4 m (2I) carrying a 50 kN load at mid-span (2 m from B), CD = 5 m (I) carrying 60 kN/m, and D on a roller; column CE (I, 6 m) runs down from C to its fixed base E. A second 50 kN load acts vertically at C (it passes through the axis of column CE and produces no bending moment). The 150 kN load at B acts to the right. The roller at D allows horizontal movement, so the frame sways; the moment distribution is done for the non-sway case and the sway case.
Distribution factors (; the hinged-end member CD gets the factor 3/4)
- Joint B: relative stiffness = 0.7000; BA: = 0.2000, DF = 0.2857; BC: = 0.5000, DF = 0.7143
- Joint C: relative stiffness = 0.8167; CB: = 0.5000, DF = 0.6122; CD: = 0.1500 (far end hinged: 3/4 factor), DF = 0.1837; CE: = 0.1667, DF = 0.2041
Case I: sway prevented by an imaginary support at B
Fixed-end moments: BC kNm; CD kNm (modified at C for the hinge at D: -187.50 kNm).
| AB | BA | BC | CB | CD | CE | EC | |
|---|---|---|---|---|---|---|---|
| DF | - | 0.286 | 0.714 | 0.612 | 0.184 | 0.204 | - |
| FEM | 0.00 | 0.00 | -25.00 | 25.00 | -187.50 | 0.00 | 0.00 |
| Balance | 0.00 | 7.14 | 17.86 | 99.49 | 29.85 | 33.16 | 0.00 |
| Carry-over | 3.57 | 0.00 | 49.74 | 8.93 | 0.00 | 0.00 | 16.58 |
| Balance | 0.00 | -14.21 | -35.53 | -5.47 | -1.64 | -1.82 | 0.00 |
| Carry-over | -7.11 | 0.00 | -2.73 | -17.77 | 0.00 | 0.00 | -0.91 |
| Balance | 0.00 | 0.78 | 1.95 | 10.88 | 3.26 | 3.63 | 0.00 |
| Carry-over | 0.39 | 0.00 | 5.44 | 0.98 | 0.00 | 0.00 | 1.81 |
| Balance | 0.00 | -1.55 | -3.88 | -0.60 | -0.18 | -0.20 | 0.00 |
| Carry-over | -0.78 | 0.00 | -0.30 | -1.94 | 0.00 | 0.00 | -0.10 |
| Further cycles (converged) | -0.05 | -0.09 | 0.39 | 1.14 | 0.38 | 0.42 | 0.21 |
| Final M | -3.97 | -7.94 | 7.94 | 120.64 | -155.83 | 35.19 | 17.59 |
The horizontal reaction of the imaginary support (positive to the right) is kN; this is the force that the imaginary support must supply to prevent sway and that the sway correction has to remove.
Case II: sway with no loads
Give the girder a sway to the right such that the fixed-end moment in AB is kNm at each end. Since and both columns move equally, column CE (EI, 6 m) gets kNm.
| AB | BA | BC | CB | CD | CE | EC | |
|---|---|---|---|---|---|---|---|
| DF | - | 0.286 | 0.714 | 0.612 | 0.184 | 0.204 | - |
| FEM | -100.00 | -100.00 | 0.00 | 0.00 | 0.00 | -138.89 | -138.89 |
| Balance | 0.00 | 28.57 | 71.43 | 85.03 | 25.51 | 28.34 | 0.00 |
| Carry-over | 14.29 | 0.00 | 42.52 | 35.71 | 0.00 | 0.00 | 14.17 |
| Balance | 0.00 | -12.15 | -30.37 | -21.87 | -6.56 | -7.29 | 0.00 |
| Carry-over | -6.07 | 0.00 | -10.93 | -15.18 | 0.00 | 0.00 | -3.64 |
| Balance | 0.00 | 3.12 | 7.81 | 9.30 | 2.79 | 3.10 | 0.00 |
| Carry-over | 1.56 | 0.00 | 4.65 | 3.90 | 0.00 | 0.00 | 1.55 |
| Balance | 0.00 | -1.33 | -3.32 | -2.39 | -0.72 | -0.80 | 0.00 |
| Carry-over | -0.66 | 0.00 | -1.20 | -1.66 | 0.00 | 0.00 | -0.40 |
| Further cycles (converged) | 0.11 | 0.22 | 0.97 | 1.12 | 0.25 | 0.28 | 0.14 |
| Final M | -90.78 | -81.56 | 81.56 | 93.97 | 21.28 | -115.25 | -127.07 |
The horizontal reaction of the imaginary support is kN.
Combination
| End | Case I | k × Case II | Final M (kNm) |
|---|---|---|---|
| AB | -3.97 | -248.31 | -252.28 |
| BA | -7.94 | -223.09 | -231.03 |
| BC | 7.94 | 223.09 | 231.03 |
| CB | 120.64 | 257.04 | 377.68 |
| CD | -155.83 | 58.20 | -97.63 |
| CE | 35.19 | -315.23 | -280.05 |
| EC | 17.59 | -347.57 | -329.97 |
Checks: Joint B: ; Joint C: ; hinge D: .
| Member | BM at first end | BM at second end | Max within member |
|---|---|---|---|
| AB | -252.28 | 231.03 | - |
| BC | 231.03 | -377.68 | - |
| CD | -97.63 | 0.00 | 141.86 at 2.83 m |
| CE | -280.05 | 329.97 | - |
Answer: , , , , , , kNm (clockwise end moments +).
✓ Answer checked by Claude Opus 5.5 (high effort)
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