Skip to main content

Plastic moment capacity of frame

Short answer

Applying virtual work to beam, sway, and combined mechanisms, the largest required plastic moment capacity is from the sway mechanism: Mp = 120 kN·m.

Find the plastic moment capacity of the frame shown in figure below. [Figure: portal frame ABCD, A and D hinged; column AB (3I) with 20 kN/m UDL horizontally; beam BC (1.5I) with 80 kN vertical at 2 m from B, span 6 m (2 m + 4 m); column CD (2I) with 100 kN horizontal at 2 m above D, heights 2 m + 2 m marked.]

Assumptions

  • Portal frame: A (0,0) and D (6,0) hinged, B (0,4), C (6,4); both columns are 4 m high, the beam is 6 m with the 80 kN at 2 m from B.
  • The plastic moments are in proportion to II: MAB=3MpM_{AB} = 3M_p, MBC=1.5MpM_{BC} = 1.5M_p, MCD=2MpM_{CD} = 2M_p, where MpM_p is the plastic moment capacity to be found. The loads are taken as ultimate (collapse) loads: 20 kN/m on AB and 100 kN on CD (2 m above D), both horizontal towards the right, and 80 kN vertical on the beam.
  • Method: virtual work for each mechanism, Mp∑(factor×θ)=∑PδM_p\sum(\text{factor}\times\theta) = \sum P\delta; the required MpM_p is the largest value obtained from all mechanisms.
  • Two hinged bases give 4 reactions, so the degree of indeterminacy is 1 and a mechanism needs 2 hinges (sway) or 3 hinges (beam).

Mechanisms

Mechanism 1: beam mechanism

No sway. Hinges at B, under the 80 kN load (2 m from B) and at C, all in the beam (1.5Mp1.5M_p is smaller than the column moments 3Mp3M_p and 2Mp2M_p). The beam parts rotate 2θ/32\theta/3 (hinge at B) and θ/3\theta/3 (hinge at C), with θ\theta under the load.

HingeRotationPlastic momentInternal work
under the 80 kN load1θ1\theta32Mp\frac{3}{2}M_p32 Mpθ\frac{3}{2}\,M_p\theta
B (beam end)23θ\frac{2}{3}\theta32Mp\frac{3}{2}M_p1 Mpθ1\,M_p\theta
C (beam end)13θ\frac{1}{3}\theta32Mp\frac{3}{2}M_p12 Mpθ\frac{1}{2}\,M_p\theta

Internal work =3 Mp θ= 3\,M_p\,\theta.

LoadDisplacement along the loadExternal work
80 kN43θ\frac{4}{3}\theta3203 kN⋅m θ\frac{320}{3}\,\text{kN·m}\,\theta
100 kN0θ0\theta0 kN⋅m θ0\,\text{kN·m}\,\theta
20 kN/m on AB-0 kN⋅m θ0\,\text{kN·m}\,\theta

Equation: Mp×3 θ=3203 θM_p\times 3\,\theta = \frac{320}{3}\,\theta (kN·m), so Mp=3209=35.56M_p = \frac{320}{9} = 35.56 kN·m.

Mechanism 2: sway mechanism

Both columns rotate θ\theta about their hinged bases, the beam translates by 4θ4\theta to the right. Hinges form at B and C in the beam, each rotating θ\theta.

HingeRotationPlastic momentInternal work
B (beam end)1θ1\theta32Mp\frac{3}{2}M_p32 Mpθ\frac{3}{2}\,M_p\theta
C (beam end)1θ1\theta32Mp\frac{3}{2}M_p32 Mpθ\frac{3}{2}\,M_p\theta

Internal work =3 Mp θ= 3\,M_p\,\theta.

LoadDisplacement along the loadExternal work
80 kN0θ0\theta0 kN⋅m θ0\,\text{kN·m}\,\theta
100 kN2θ2\theta200 kN⋅m θ200\,\text{kN·m}\,\theta
20 kN/m on AB-160 kN⋅m θ160\,\text{kN·m}\,\theta

Equation: Mp×3 θ=360 θM_p\times 3\,\theta = 360\,\theta (kN·m), so Mp=120M_p = 120 kN·m.

Mechanism 3: combined mechanism

Beam and sway mechanisms combined so that the hinge at B cancels; hinges under the 80 kN load and at C.

HingeRotationPlastic momentInternal work
under the 80 kN load1θ1\theta32Mp\frac{3}{2}M_p32 Mpθ\frac{3}{2}\,M_p\theta
C (beam end)1θ1\theta32Mp\frac{3}{2}M_p32 Mpθ\frac{3}{2}\,M_p\theta

Internal work =3 Mp θ= 3\,M_p\,\theta.

LoadDisplacement along the loadExternal work
80 kN43θ\frac{4}{3}\theta3203 kN⋅m θ\frac{320}{3}\,\text{kN·m}\,\theta
100 kN43θ\frac{4}{3}\theta4003 kN⋅m θ\frac{400}{3}\,\text{kN·m}\,\theta
20 kN/m on AB-3203 kN⋅m θ\frac{320}{3}\,\text{kN·m}\,\theta

Equation: Mp×3 θ=10403 θM_p\times 3\,\theta = \frac{1040}{3}\,\theta (kN·m), so Mp=10409=115.56M_p = \frac{1040}{9} = 115.56 kN·m.

Required plastic moment

The largest required MpM_p comes from the sway mechanism (the others give 35.56 and 115.56 kN·m); a frame with MpM_p smaller than this would collapse in sway, while a larger value is safe against all mechanisms.

Answer: Mp=120M_p = 120 kN·m (so MAB=360M_{AB} = 360, MBC=180M_{BC} = 180, MCD=240M_{CD} = 240 kN·m).

✓ Answer checked by Claude Opus 5.5 (high effort)

All Theory of Structures II chapter 5 questions →