- 2076 Chaitra · 10 marks
Plastic moment capacity of frame
Short answer
Applying virtual work to beam, sway, and combined mechanisms, the largest required plastic moment capacity is from the sway mechanism: Mp = 120 kN·m.
Find the plastic moment capacity of the frame shown in figure below. [Figure: portal frame ABCD, A and D hinged; column AB (3I) with 20 kN/m UDL horizontally; beam BC (1.5I) with 80 kN vertical at 2 m from B, span 6 m (2 m + 4 m); column CD (2I) with 100 kN horizontal at 2 m above D, heights 2 m + 2 m marked.]
Assumptions
- Portal frame: A (0,0) and D (6,0) hinged, B (0,4), C (6,4); both columns are 4 m high, the beam is 6 m with the 80 kN at 2 m from B.
- The plastic moments are in proportion to : , , , where is the plastic moment capacity to be found. The loads are taken as ultimate (collapse) loads: 20 kN/m on AB and 100 kN on CD (2 m above D), both horizontal towards the right, and 80 kN vertical on the beam.
- Method: virtual work for each mechanism, ; the required is the largest value obtained from all mechanisms.
- Two hinged bases give 4 reactions, so the degree of indeterminacy is 1 and a mechanism needs 2 hinges (sway) or 3 hinges (beam).
Mechanisms
Mechanism 1: beam mechanism
No sway. Hinges at B, under the 80 kN load (2 m from B) and at C, all in the beam ( is smaller than the column moments and ). The beam parts rotate (hinge at B) and (hinge at C), with under the load.
| Hinge | Rotation | Plastic moment | Internal work |
|---|---|---|---|
| under the 80 kN load | |||
| B (beam end) | |||
| C (beam end) |
Internal work .
| Load | Displacement along the load | External work |
|---|---|---|
| 80 kN | ||
| 100 kN | ||
| 20 kN/m on AB | - |
Equation: (kN·m), so kN·m.
Mechanism 2: sway mechanism
Both columns rotate about their hinged bases, the beam translates by to the right. Hinges form at B and C in the beam, each rotating .
| Hinge | Rotation | Plastic moment | Internal work |
|---|---|---|---|
| B (beam end) | |||
| C (beam end) |
Internal work .
| Load | Displacement along the load | External work |
|---|---|---|
| 80 kN | ||
| 100 kN | ||
| 20 kN/m on AB | - |
Equation: (kN·m), so kN·m.
Mechanism 3: combined mechanism
Beam and sway mechanisms combined so that the hinge at B cancels; hinges under the 80 kN load and at C.
| Hinge | Rotation | Plastic moment | Internal work |
|---|---|---|---|
| under the 80 kN load | |||
| C (beam end) |
Internal work .
| Load | Displacement along the load | External work |
|---|---|---|
| 80 kN | ||
| 100 kN | ||
| 20 kN/m on AB | - |
Equation: (kN·m), so kN·m.
Required plastic moment
The largest required comes from the sway mechanism (the others give 35.56 and 115.56 kN·m); a frame with smaller than this would collapse in sway, while a larger value is safe against all mechanisms.
Answer: kN·m (so , , kN·m).
✓ Answer checked by Claude Opus 5.5 (high effort)
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