- 2078 Bhadra · 8 marks
Demand of rural area survey 2019, 1.77% growth
Short answer
Population grows geometrically at 1.77% for 22 years to 6,561. Applying rural unit demands and 15% losses gives total water demand 382 m3/day, about 4.42 l/s.
A survey was carried out in 2019 in a rural area of Nepal and the following data were obtained: Population = 4460, Offices = 3 nos, Day students = 654, boarding students = 145, Cows and buffaloes = 480, goats and pigs = 855. A 15% of net water demand is considered as compensation for losses and wastage. Estimate the total water demand for the scheme if base period is 2 years and design period is 20 years. Consider the annual population growth rate as 1.77%.
Survey year 2019; base period 2 years and design period 20 years, so the design year is 2041, i.e. years after the survey.
Design population
Water demand
Design values assumed (Nepal rural water supply practice): domestic 45 lpcd (public taps); day scholar 5 l/d; boarder 45 l/d; office staff 45 l/d with 10 staff per office; big animal (cow, buffalo) 45 l/d; small animal (goat, pig) 5 l/d; poultry 0.2 l/d; health post 1000 l/d; tea shop 500 l/d; losses and wastage 15% of net demand; maximum day factor 1.5 and peak hour factor 3. Losses and wastage are 15% of net demand as given. Student and livestock numbers are taken as constant.
| Demand | Quantity | Rate | Demand (l/day) |
|---|---|---|---|
| Domestic (45 lpcd) | 6,561 | 45 l/c/d | 295,245 |
| Day students | 654 | 5 l/c/d | 3,270 |
| Boarding students | 145 | 45 l/c/d | 6,525 |
| Offices (10 staff each) | 30 | 45 l/staff | 1,350 |
| Cows + buffaloes | 480 | 45 l/d | 21,600 |
| Goats + pigs | 855 | 5 l/d | 4,275 |
| Net demand | 332,265 |
Losses and wastage of net demand l/day
Answer: Design population = 6,561; total water demand = 382 m/day (4.42 l/s).
✓ Answer checked by Claude Opus 5.5 (high effort)
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