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Building types, mechanical ventilation, air flow

Short answer

Residential building: for living/sleeping (houses, flats, hotels). Institutional building: for medical care/custody (hospitals, clinics, jails). Mechanical ventilation types: extract (exhaust) system, plenum (supply) system, balanced (supply+exhaust) system, ducted system with air-handling unit. For given openings, effective area A = 0.08856 m²; airflow Q = E×A×V = 0.33 × 0.08856 × 1.389 = 0.0406 m³/s = 146.1 m³/h.

Define residential and institutional building. Explain types of mechanical ventilation system. Calculate the rate of air flow through two square openings of size 0.32m and 0.42m in a 4m×4m×4m room, with a wind of 5 km/hr blowing inclined at 45° to the opening. Take Coefficient of effectiveness =0.33.

Residential building

A building used for living and sleeping: houses, flats, apartments, hostels, hotels.

Institutional building

A building used for medical treatment, care or custody of people, where they stay or attend: hospitals, clinics, sanatoriums, homes for the aged, orphanages, jails. (Some textbooks also include schools and colleges, but the building code treats educational buildings as a separate class.)

Types of mechanical ventilation

  1. Extract (exhaust) system: Fans remove air from the room, and fresh air comes in through openings. Used in kitchens, toilets and factories. It creates negative pressure.
  2. Plenum (supply or positive-pressure) system: A fan forces filtered air in, and stale air leaves through openings. Used in hospital operating theatres and clean rooms.
  3. Balanced (combined supply and extract) system: Both supply and exhaust fans are used, so the pressure is balanced. Used in theatres, halls and basements.
  4. Ducted system with air-handling unit: A central fan, filters and ducts distribute the air; it can be combined with air conditioning.
 Extract:  out <-[fan]  room  <- air leaks in
 Plenum:   in ->[fan]   room  -> air leaks out
 Balanced: in ->[fan] room [fan]-> out

Given

  • Inlet and outlet openings: 0.32 m × 0.32 m and 0.42 m × 0.42 m, so A1=0.1024 m2A_1 = 0.1024\ \text{m}^2 and A2=0.1764 m2A_2 = 0.1764\ \text{m}^2
  • Wind speed v=5v = 5 km/h =5/3.6=1.3889= 5/3.6 = 1.3889 m/s, at 45° to the opening
  • Coefficient of effectiveness E=0.33E = 0.33 (already accounts for the wind direction; the room size does not enter the formula)

Formula

For wind-driven ventilation through two openings in series, the effective area is

A=A1A2A12+A22,Q=E A VA = \frac{A_1 A_2}{\sqrt{A_1^2 + A_2^2}}, \qquad Q = E\, A\, V

Calculation

A=0.1024×0.17640.10242+0.17642=0.08856 m2Q=0.33×0.08856×1.3889=0.04059 m3/s\begin{aligned} A &= \frac{0.1024 \times 0.1764}{\sqrt{0.1024^2 + 0.1764^2}} = 0.08856\ \text{m}^2 \\ Q &= 0.33 \times 0.08856 \times 1.3889 = 0.04059\ \text{m}^3/\text{s} \end{aligned}

Answer: Q=0.0406Q = 0.0406 m³/s =146.1= 146.1 m³/h.

✓ Answer checked by Claude Opus 5.5 (high effort)

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