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PSD of a power signal and its interpretation

Short answer

For power signals with infinite energy, PSDF S_g(f) = lim_{T→∞} |G_T(f)|²/T (W/Hz) describes average power per unit bandwidth. It is derived by truncating the signal, applying Rayleigh's theorem, and taking the limit. S_g(f) is real, non-negative, even, and its integral gives total power. It carries no phase information and relates to autocorrelation via Wiener-Khinchin theorem.

Derive the expression for power spectral density function (psdf) for a power type signal. Give the interpretation of psdf.

A power signal g(t)g(t) has finite, non-zero average power and infinite energy, so its Fourier transform generally does not exist in the ordinary sense. Its frequency content is described by the power spectral density function (PSDF) Sg(f)S_g(f), the average power per unit bandwidth.

Derivation

Step 1 – truncate the signal to a window of length TT:

gT(t)=g(t) rect(tT)={g(t),∣t∣≤T/20,otherwiseg_T(t)=g(t)\,\text{rect}\left(\frac{t}{T}\right)=\begin{cases}g(t), & \lvert t\rvert\le T/2\\0, & \text{otherwise}\end{cases}

gT(t)g_T(t) has finite energy, so its Fourier transform GT(f)G_T(f) exists.

Step 2 – average power of g(t)g(t):

P=lim⁡T→∞1T∫−T/2T/2∣g(t)∣2dt=lim⁡T→∞1T∫−∞∞∣gT(t)∣2dtP=\lim_{T\to\infty}\frac{1}{T}\int_{-T/2}^{T/2}\lvert g(t)\rvert^2dt=\lim_{T\to\infty}\frac{1}{T}\int_{-\infty}^{\infty}\lvert g_T(t)\rvert^2dt

Step 3 – Rayleigh's energy theorem for gT(t)g_T(t):

∫−∞∞∣gT(t)∣2dt=∫−∞∞∣GT(f)∣2df\int_{-\infty}^{\infty}\lvert g_T(t)\rvert^2dt=\int_{-\infty}^{\infty}\lvert G_T(f)\rvert^2df

Step 4 – combine:

P=lim⁡T→∞1T∫−∞∞∣GT(f)∣2df=∫−∞∞lim⁡T→∞∣GT(f)∣2T df\begin{aligned} P&=\lim_{T\to\infty}\frac{1}{T}\int_{-\infty}^{\infty}\lvert G_T(f)\rvert^2df\\ &=\int_{-\infty}^{\infty}\lim_{T\to\infty}\frac{\lvert G_T(f)\rvert^2}{T}\,df \end{aligned}

Step 5 – define PSDF. Since total power must equal ∫Sg(f)df\int S_g(f)df:

Sg(f)=lim⁡T→∞∣GT(f)∣2T(W/Hz)S_g(f)=\lim_{T\to\infty}\frac{\lvert G_T(f)\rvert^2}{T}\quad(\text{W/Hz})

Alternative form (Wiener–Khinchin): the time-averaged autocorrelation Rg(τ)=lim⁡T→∞1T∫−T/2T/2g(t)g∗(t−τ)dtR_g(\tau)=\lim_{T\to\infty}\frac{1}{T}\int_{-T/2}^{T/2}g(t)g^*(t-\tau)dt and the PSD form a Fourier pair:

Sg(f)=∫−∞∞Rg(τ)e−j2πfτdτ,Rg(0)=P=∫−∞∞Sg(f)dfS_g(f)=\int_{-\infty}^{\infty}R_g(\tau)e^{-j2\pi f\tau}d\tau,\qquad R_g(0)=P=\int_{-\infty}^{\infty}S_g(f)df

Example: for g(t)=Acos⁡2πfctg(t)=A\cos2\pi f_ct, Rg(τ)=A22cos⁡2πfcτR_g(\tau)=\frac{A^2}{2}\cos2\pi f_c\tau, so Sg(f)=A24[δ(f−fc)+δ(f+fc)]S_g(f)=\frac{A^2}{4}[\delta(f-f_c)+\delta(f+f_c)] and P=A2/2P=A^2/2.

Interpretation of PSDF

  1. Sg(f) dfS_g(f)\,df is the average power contained in a narrow band dfdf at frequency ff; the PSDF shows how the power is distributed over frequency.
  2. Area = average power: P=∫Sg(f)dfP=\int S_g(f)df. Power in a band f1f_1 to f2f_2 (both sides) is 2∫f1f2Sg(f)df2\int_{f_1}^{f_2}S_g(f)df for real signals.
  3. It is real, non-negative and even (Sg(−f)=Sg(f)S_g(-f)=S_g(f)) for real signals.
  4. It carries no phase information: different signals can have the same PSDF.
  5. Measured by a filter: if g(t)g(t) is passed through an ideal narrow band-pass filter of bandwidth Δf\Delta f at ff, the output power is about 2Sg(f)Δf2S_g(f)\Delta f. This is how a spectrum analyzer measures PSD.
  6. Through an LTI system: Sy(f)=∣H(f)∣2Sg(f)S_y(f)=\lvert H(f)\rvert^2S_g(f), used to compute output noise power and filter design.
  7. For periodic signals the PSDF is a set of impulses of weight ∣cn∣2\lvert c_n\rvert^2 at harmonics nf0nf_0; for random noise it is continuous (e.g. white noise S(f)=N0/2S(f)=N_0/2).

✓ Answer checked by Claude Opus 5.5 (high effort)

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