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Effect of lateral restraint on moment capacity

Short answer

Restrained compression flange achieves full plastic capacity M_d = β_b Z_p f_y / γ_m0. Unrestrained length causes lateral-torsional buckling, reducing capacity to M_d = β_b Z_p f_bd, where f_bd = χ_LT f_y/γ_m0 and χ_LT < 1 decreases as span increases.

What is the effect of laterally restrained and unrestrained compression flange in bending moment carrying capacity of beam?

The bending moment capacity of a beam depends on whether its compression flange is held against sideways movement.

Laterally restrained compression flange

The flange cannot buckle sideways, so the beam fails only when the section yields. The full plastic (or elastic) section strength is available (IS 800:2007 cl. 8.2.1):

Md=βbZpfyγm0≤1.2Zefyγm0M_d = \frac{\beta_bZ_pf_y}{\gamma_{m0}} \le \frac{1.2Z_ef_y}{\gamma_{m0}}

where βb=1\beta_b = 1 for plastic and compact sections, and Ze/ZpZ_e/Z_p for semi-compact ones.

Laterally unrestrained compression flange

The compression flange behaves like a column and tends to buckle sideways with a twist (lateral-torsional buckling, cl. 8.2.2). The capacity is reduced:

Md=βbZpfbd,fbd=χLTfyγm0,χLT=1ϕLT+ϕLT2−λLT2≤1M_d = \beta_bZ_pf_{bd},\quad f_{bd} = \chi_{LT}\frac{f_y}{\gamma_{m0}},\quad \chi_{LT} = \frac{1}{\phi_{LT} + \sqrt{\phi_{LT}^2 - \lambda_{LT}^2}} \le 1

with λLT=βbZpfy/Mcr\lambda_{LT} = \sqrt{\beta_bZ_pf_y/M_{cr}}. The longer the unrestrained length and the smaller IyI_y, ItI_t, IwI_w, the smaller McrM_{cr} and the lower the capacity.

Example: ISMB 400, Fe 410 (computed with the IS 800 formulas)

Plastic modulus Zp=1161Z_p = 1161 cm³, restrained capacity Md=264M_d = 264 kN·m.

Unrestrained length (m)McrM_{cr} (kN·m)χLT\chi_{LT}MdM_d (kN·m)Fraction of restrained MdM_d
124490.9725597%
26770.8722987%
33430.7219072%
42220.5715057%
61290.379837%
8910.277227%

Practical effect

  • Short unrestrained length (about λLT≤0.4\lambda_{LT} \le 0.4): no loss of capacity.
  • A long unbraced length can cut the capacity to less than half; the beam then needs a larger section or lateral bracing.
  • Restraint is obtained from a connected slab, cross beams, bracing or end torsional restraint, and a larger IyI_y (wider flange) improves the unrestrained strength.

✓ Answer checked by Claude Opus 5.5 (high effort)

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