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Check eccentric fillet weld, 8 mm, P=100 kN

Short answer

The weld experiences direct shear and bending moment, giving resultant stress 155.9 MPa. This exceeds the permissible shear stress of 108 MPa. Hence the joint is not safe.

For the electric (eccentric) connection as shown, determine whether the joint is safe or not. Size of the fillet weld is 8mm and load P is equal to 100KN. Assume that permissible shear stress in the weld is 108 MPa. [Figure: 14 mm thick gusset plate welded to a column flange with 20 cm weld width at top and bottom and 20 cm depth; P = 100 kN acts at 40 cm from the weld face; 20 cm dimension marked]

Basis: working stress method (permissible shear stress in weld 108 N/mm²). The gusset (14 mm) is welded to the column flange by a C-shaped fillet weld: top and bottom 200 mm and vertical 200 mm. P=100P=100 kN acts parallel to the flange at e=400e=400 mm from the weld plane, giving direct shear and bending. Weld size s=8s=8 mm, throat tt=0.7×8=5.6t_t=0.7\times8=5.6 mm.

Weld group (per mm of throat)

  • L=2×200+200=600L=2\times200+200=600 mm
  • Ixx=200312+2×200×1002=4666667I_{xx}=\dfrac{200^3}{12}+2\times200\times100^2=4666667 mm³
  • M=100×103×400=40×106M=100\times10^3\times400=40\times10^6 N·mm

Force per mm of weld at the extreme weld (y = 100 mm)

  • Shear: qs=PL=100000600=166.7q_s=\dfrac{P}{L}=\dfrac{100000}{600}=166.7 N/mm
  • Bending: qb=MyIxx=40×106×1004666667=857.1q_b=\dfrac{My}{I_{xx}}=\dfrac{40\times10^6\times100}{4666667}=857.1 N/mm
  • Resultant q=qs2+qb2=873.2q=\sqrt{q_s^2+q_b^2}=873.2 N/mm

Stress in the weld

τ=qtt=873.25.6=155.9 N/mm2>108 N/mm2\tau=\frac{q}{t_t}=\frac{873.2}{5.6}=155.9\ \text{N/mm}^2>108\ \text{N/mm}^2

Answer: the joint is NOT safe (stress is about 156 N/mm² against 108 N/mm² permissible). It needs a larger weld (about 12 mm) or a deeper weld.

✓ Answer checked by Claude Opus 5.5 (high effort)

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