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Failure modes and stability criteria of gravity dams

Short answer

Gravity dams may fail by overturning (FSo ≥1.5), sliding (FSs ≥1, SFF ≥3-5), crushing (toe stress ≤ allowable), or tension cracking (resultant within middle third, e ≤ B/6). Design must satisfy these criteria under all loading conditions.

Explain the failure modes and the structural stability criteria of gravity dams.

A gravity dam resists the water thrust and other forces mainly by its own weight. It can fail in four ways; each one gives a stability criterion that the design must satisfy for all load combinations (empty reservoir, full reservoir, earthquake, flood).

     |\           W = self weight
 P-> | \          P = water thrust
     |  \         U = uplift
 ~~~~|   \        R = resultant
     | W  \
     |  \  \
heel |___R__\ toe
     ^ U ^ ^ ^

1. Overturning about the toe

  • Mode: the horizontal forces (water pressure, silt, wave, earthquake) and uplift produce a moment that tends to rotate the dam about its toe.
  • Criterion: factor of safety against overturning
FSo=∑MR∑MO≥1.5 (usually 2 to 3)FS_o = \frac{\sum M_R}{\sum M_O} \geq 1.5\ (\text{usually } 2 \text{ to } 3)

In practice, a dam that satisfies the no-tension and crushing criteria will not overturn.

2. Sliding (shear failure)

  • Mode: the dam slides along the base or along a weak joint/seam in the foundation when the horizontal force exceeds the frictional and shear resistance.
  • Criteria:
    • Factor of safety against sliding (friction only): FSs=μ∑V∑H≥1FS_s = \dfrac{\mu \sum V}{\sum H} \geq 1 (usually 1 to 1.5).
    • Shear friction factor (friction plus shear strength qq of the joint over base width BB): SFF=μ∑V+Bq∑H≥3SFF = \dfrac{\mu \sum V + B q}{\sum H} \geq 3 to 5.

3. Compression or crushing

  • Mode: the vertical stress at the toe (full reservoir) or heel (empty reservoir) exceeds the allowable compressive strength of concrete or rock.
  • Criterion:
pmax=∑VB(1+6eB)≤allowable stressp_{max} = \frac{\sum V}{B}\left(1 + \frac{6e}{B}\right) \leq \text{allowable stress}

The principal stress at the toe, σ1=pvsec⁡2α−p′tan⁡2α\sigma_1 = p_v\sec^2\alpha - p'\tan^2\alpha, must also be below the allowable value.

4. Tension cracking

  • Mode: if the resultant falls outside the middle third of the base (e>B/6e > B/6), tension develops at the heel. Concrete is weak in tension, so a crack opens, uplift enters the crack, the effective base width reduces and stresses at the toe rise, which can lead to failure.
  • Criterion (middle-third rule):
e≤B6⇒pmin=∑VB(1−6eB)≥0e \leq \frac{B}{6} \quad\Rightarrow\quad p_{min} = \frac{\sum V}{B}\left(1 - \frac{6e}{B}\right) \geq 0

A small tension (e.g. up to about 500 kN/m²) is sometimes allowed for extreme load cases such as earthquakes.

Summary of criteria

Failure modeCriterion
OverturningFSo≥1.5FS_o \geq 1.5
SlidingFSs≥1FS_s \geq 1; SFF≥3SFF \geq 3–5
Crushingpmax≤p_{max} \leq allowable
TensionResultant in middle third (e≤B/6e \leq B/6)

✓ Answer checked by Claude Opus 5.5 (high effort)

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