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Types of heads and Bernoulli's assumptions

Short answer

Heads are pressure head p/ρg, velocity head V^2/2g, and potential head z. Bernoulli's equation: p/ρg + V^2/2g + z = constant along a streamline for steady, incompressible, ideal flow with no energy added or removed. Assumptions: ideal fluid, steady, incompressible, irrotational, uniform velocity, no pump/turbine.

Briefly explain the different types of heads in a moving liquid. Define Bernoulli's equation and list the assumptions made in its derivation.

In a moving liquid the energy per unit weight is called head (unit m). There are three main heads.

Types of heads

  1. Pressure head, p/ρgp/\rho g: energy due to pressure; the height of liquid column the pressure can support.
  2. Velocity (kinetic) head, V2/2gV^2/2g: energy due to motion; the height a particle would rise if its velocity were turned upwards.
  3. Potential (datum) head, zz: energy due to position above an arbitrary datum.
  • Piezometric head =p/ρg+z= p/\rho g + z (level shown by a piezometer, defines the HGL).
  • Total head H=p/ρg+V2/2g+zH = p/\rho g + V^2/2g + z (defines the energy line). In real flows a loss of head hLh_L due to friction and fittings also appears.

Bernoulli's equation

For steady, ideal, incompressible flow along a streamline, the total head is constant:

pρg+V22g+z=constant\frac{p}{\rho g} + \frac{V^2}{2g} + z = \text{constant}

or between sections 1 and 2:

p1ρg+V122g+z1=p2ρg+V222g+z2\frac{p_1}{\rho g} + \frac{V_1^2}{2g} + z_1 = \frac{p_2}{\rho g} + \frac{V_2^2}{2g} + z_2

Assumptions

  1. The fluid is ideal (non-viscous), so there is no friction loss.
  2. The flow is steady.
  3. The flow is incompressible (ρ\rho constant).
  4. The flow is irrotational and the equation is applied along a streamline.
  5. Only gravity and pressure forces act; no energy is added or removed (no pump or turbine) and no heat transfer.
  6. Velocity is uniform over the section (one-dimensional flow).

✓ Answer checked by Claude Opus 5.5 (high effort)

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