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Measuring pressure difference in a pipe

Short answer

A differential manometer uses a U-tube with heavy liquid. For points at different levels: pA − pB = ρ_g g h + ρ_2 g h_B − ρ_1 g h_A. If in the same horizontal pipe with the same liquid: pA − pB = gh(ρ_g − ρ).

How do you measure difference of pressure between any two points in a pipe? Explain with neat sketch and mathematical expression.

The pressure difference between two points in a pipe (or between two pipes) is measured with a differential manometer: a U-tube containing a heavy manometric liquid (usually mercury), with its two limbs connected to the two points.

U-tube differential manometer (points at different levels)

     A o                     
       |  pipe liquid S1      o B
       |                      |  pipe liquid S2
       | h_A                  | h_B
       |       h              |
   X --+-----.  .-------------+
       |  Hg |  | Hg surface
        \____|__|____/
          mercury (S_g)

Let A be hAh_A above the datum X–X (the lower mercury surface), B be hBh_B above the higher mercury surface, and hh the difference between the mercury levels.

Pressure at X–X in the left limb =pA+ρ1ghA= p_A + \rho_1 g h_A. Pressure at X–X in the right limb =pB+ρ2ghB+ρggh= p_B + \rho_2 g h_B + \rho_g g h.

pA−pB=ρggh+ρ2ghB−ρ1ghAp_A - p_B = \rho_g g h + \rho_2 g h_B - \rho_1 g h_A

Both points at the same level, same liquid

If A and B are in the same horizontal pipe carrying a liquid of density ρ\rho:

pA−pB=gh(ρg−ρ)p_A - p_B = g h(\rho_g - \rho)

For water and mercury: pA−pB=12.6 ρwghp_A - p_B = 12.6\,\rho_w g h.

Inverted U-tube manometer

For small pressure differences, a light liquid (air or oil) is used at the top of an inverted U-tube:

pA−pB=ρ1gh1−ρ2gh2−ρsghp_A - p_B = \rho_1 g h_1 - \rho_2 g h_2 - \rho_s g h

where h1h_1 and h2h_2 are the depths of A and B below their interfaces with the light liquid, hh is the level difference between the two interfaces, and ρs\rho_s is the density of the light liquid.

Steps of measurement

  1. Connect each limb to its pipe tapping, filling the leads with the pipe liquid (no air bubbles).
  2. Let the manometer settle and read the level difference hh.
  3. Choose a datum at the lower interface and equate the pressures in both limbs.

Other devices: a pair of Bourdon gauges, or electronic differential pressure transducers, for large differences.

✓ Answer checked by Claude Opus 5.5 (high effort)

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