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Khosla's method for barrage floor design

Short answer

Design steps: determine data, scour depth via Lacey, maximum static head, floor length from exit gradient formula, pressures at key points with mutual interference, floor thickness, and slope corrections, then floor thickness t = (4/3)h/(G-1), provide aprons and check. Typical section includes gates, crest, upstream floor, glacis, downstream jump floor, upstream/downstream cutoffs, intermediate piles, aprons with filters, and wing walls.

Explain the design method to find the suitable size, length and thickness of floor of barrage using Khosla's seepage theory. Also draw the typical section of barrage showing the different components.

Khosla's method for the design of a barrage floor

Khosla's theory gives the pressure and exit gradient from the flow of seepage water below the floor. The floor is designed in the following steps.

Step 1: Data. Maximum flood discharge, HFL, pond level (PL), d/s tail water level, bed level, silt factor ff, safe exit gradient GEG_E (1/5 to 1/7 for sand), specific gravity of floor material G=2.4G = 2.4.

Step 2: Scour depth. Lacey's R=1.35 (q2/f)1/3R = 1.35\,(q^2/f)^{1/3}, with qq = discharge per metre width. Use it for the cutoff depths: u/s cutoff ≥1.0R\ge 1.0R-1.5R1.5R below HFL and d/s cutoff ≥1.5R\ge 1.5R-2R2R below the d/s HFL.

Step 3: Maximum static head HH = PL −- d/s bed (or floor) level with no flow (usually nil tail water); and under flow with HFL.

Step 4: Exit gradient and length of floor.

GE=Hd⋅1πλ,λ=1+1+α22, α=bdG_E = \frac{H}{d}\cdot\frac{1}{\pi\sqrt{\lambda}},\qquad \lambda = \frac{1+\sqrt{1+\alpha^2}}{2},\ \alpha = \frac{b}{d}

Taking dd as the d/s cutoff depth, find α\alpha (hence floor length bb) such that GE≤G_E \le safe value. Provide the total floor length with some margin.

Step 5: Pressures at key points. Compute ϕE,ϕD,ϕC\phi_E,\phi_D,\phi_C for each pile line:

  • u/s pile: ϕE1=100\phi_{E_1} = 100, ϕD1=100−ϕD\phi_{D_1} = 100-\phi_D, ϕC1=100−ϕE\phi_{C_1} = 100-\phi_E.
  • d/s pile: ϕE2=ϕE\phi_{E_2} = \phi_E, ϕD2=ϕD\phi_{D_2}=\phi_D, ϕC2=0\phi_{C_2}=0.

Apply corrections: (a) mutual interference of piles C=19D/b′ (d+D)/bC = 19\sqrt{D/b'}\,(d+D)/b; (b) floor thickness; (c) slope of the glacis.

Step 6: Floor thickness. Uplift head at a point hh (from corrected ϕ×H\phi\times H). Required thickness

t=43⋅hG−1(33% extra for safety)t = \frac{4}{3}\cdot\frac{h}{G-1} \quad(\text{33\% extra for safety})

The thickness is greatest near the toe of the glacis and is decreased in steps (min 0.5-0.6 m).

Step 7: Floor details. The d/s floor length is fixed by the hydraulic jump, and the thickness of the u/s floor is provided with nominal values. Provide the u/s and d/s aprons (blocks with inverted filter) of length 1.5-2 times the scour depth, with launching apron.

Step 8: Check pressure line (HGL), exit gradient, and thickness for both conditions (no flow and flow).

Typical section of a barrage

  Pond level ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
        gates (piers)             HFL ~~~~~
 u/s floor |   crest  |\ glacis | jump floor | d/s apron
 ==========|__________|  \______|============|== blocks
   u/s block apron    |         |      filter, launching
 u/s pile (cutoff)  intermediate pile     d/s pile (cutoff)

Components: gates and piers, crest, u/s floor, glacis, horizontal d/s floor (jump), u/s and d/s cutoffs, intermediate piles, aprons with filters and launching aprons, u/s and d/s wing walls.

✓ Answer checked by Claude Opus 5.5 (high effort)

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