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Khosla: HGL and d/s floor thickness, three piles

Short answer

Between intermediate and d/s piles, pressure drops linearly from 65% to 55% of total head. With 10 m net head, required floor thickness at 20 m is 5.00 m and at 30 m is 4.79 m.

Following corrected φ values were computed from Khosla's curves in a barrage placed on permeable foundation. U/S sheet pile: φE1 = 100%, φD1 = 90%, φC1 = 85% Intermediate pile: φE2 = 80%, φD2 = 70%, φC2 = 65% D/S sheet pile: φE3 = 55%, φD3 = 45%, φC3 = 0% Distance between the U/S and intermediate piles is 20 m and that between the intermediate and D/S piles is 40 m. Assuming that the floor is horizontal throughout, draw the HGL for the subsoil flow. If the net head is 10 m, determine the thickness of D/S floor at a distance of 20 m and 30 m away from the intermediate sheet pile. Assume G for the floor material equal to 2.2. The symbols has usual meanings.

Given

Corrected pressures (percent of head): u/s pile E1=100E_1 = 100, D1=90D_1 = 90, C1=85C_1 = 85; intermediate pile E2=80E_2 = 80, D2=70D_2 = 70, C2=65C_2 = 65; d/s pile E3=55E_3 = 55, D3=45D_3 = 45, C3=0C_3 = 0. Net head H=10H = 10 m, G=2.2G = 2.2. Piles at 0, 20 m and 60 m (20 m and 40 m apart). The floor is horizontal, with its level taken as the datum (d/s water level).

Hydraulic gradient line

The HGL is a vertical drop across each pile and a straight line along the floor between piles:

PointPressure (%)Head above floor (m)
E1E_110010.0
D1D_1909.0
C1C_1858.5
E2E_2808.0
D2D_2707.0
C2C_2656.5
E3E_3555.5
D3D_3454.5
C3C_300
 100 E1 |#############################
  90 D1 |##########################
  85 C1 |########################    (floor, 20 m)
  80 E2 |#######################
  70 D2 |####################
  65 C2 |##################          (floor, 40 m)
  55 E3 |################
  45 D3 |#############
   0 C3 |

Thickness of the d/s floor (between intermediate and d/s piles)

On the 40 m floor the pressure falls linearly from 65% at C2C_2 to 55% at E3E_3:

ϕ(x)=65−(65−55)x40\phi(x) = 65 - (65-55)\frac{x}{40}

Unbalanced head h=ϕH/100h = \phi H/100 and thickness t=hG−1=h1.2t = \dfrac{h}{G-1} = \dfrac{h}{1.2}:

Distance from intermediate pileϕ\phi (%)hh (m)tt (m)
20 m60.06.005.00
30 m57.55.754.79

Answer: Required floor thickness ≈5.00\approx 5.00 m at 20 m and ≈4.79\approx 4.79 m at 30 m from the intermediate sheet pile.

✓ Answer checked by Claude Opus 5.5 (high effort)

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