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Outlet discharge from kor table (rice, wheat)

Short answer

Rice: Q = (5×10⁷ ×0.19)/(18×86400) = 6.11 cumec. Wheat: Q = (3.5×10⁷ ×0.15)/(26×86400) = 2.34 cumec. Crops are in different seasons, so design discharge = 6.11 cumec (the larger).

Calculate the discharge required at the outlet for wheat and rice crop using following data.

Cropcommand area (Ha)kor periodkor depth
Rice50001819
Wheat35002615

Assumption: kor period is in days and kor depth in cm.

Formula: Q=A dT×86400Q = \dfrac{A\,d}{T\times 86400}

Rice: A=5000A = 5000 ha =5×107= 5\times10^7 m2^2, T=18T = 18 days, d=19d = 19 cm =0.19= 0.19 m

Qr=5×107×0.1918×86400=6.109 m3/sQ_r = \frac{5\times10^7\times0.19}{18\times86400} = 6.109\ \text{m}^3/\text{s}

Wheat: A=3500A = 3500 ha =3.5×107= 3.5\times10^7 m2^2, T=26T = 26 days, d=15d = 15 cm =0.15= 0.15 m

Qw=3.5×107×0.1526×86400=2.337 m3/sQ_w = \frac{3.5\times10^7\times0.15}{26\times86400} = 2.337\ \text{m}^3/\text{s}

Rice (kharif) and wheat (rabi) are grown in different seasons, so the outlet is designed for the larger value.

Answer: rice needs 6.11 cumec and wheat needs 2.34 cumec; design discharge = 6.11 cumec. (If both were irrigated together, the sum would be 8.45 cumec.)

✓ Answer checked by Claude Opus 5.5 (high effort)

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