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Minimum radius of valley curve

Short answer

From comfort criterion, minimum radius R = √(v³/(C N)) with allowable rate of change of centrifugal acceleration C = 0.6 m/s³. For night visibility with headlight height h and beam angle α, length L = N S²/[2(h + S tan α)] when L > S, and R = L/N; the larger radius governs.

Derive an expression for the minimum permissible radius of valley curve from two considerations (comfort and night visibility).

A valley (sag) curve is a vertical curve with the centre of curvature above the road. There is no obstruction to vision during the day, so the curve is designed from two criteria: comfort and headlight sight distance at night. The larger length (and radius) is adopted. The curve has length LL and algebraic difference of grades NN (as a ratio). For a simple parabola the radius of curvature is constant, R≈L/NR \approx L/N.

1. Comfort criterion

A vehicle moving at speed vv (m/s) on the vertical curve feels a centripetal acceleration v2/Rv^2/R, which should rise gradually from 0 at the start. The allowable rate of change of this acceleration is C=0.6C = 0.6 m/s³.

For this, the valley curve is treated as two transition curves (each of length L/2L/2 and deflection N/2N/2), so the radius decreases from infinity at the tangent points to a minimum RR at the middle of the curve. For a spiral transition curve, the deflection angle is Ls2R\dfrac{L_s}{2R} and LsR=v3CL_sR = \dfrac{v^3}{C}. Here, Ls=L/2L_s = L/2:

N2=L/22R ⇒ R=L2N\frac{N}{2} = \frac{L/2}{2R}\ \Rightarrow\ R = \frac{L}{2N} L2⋅L2N=v3C ⇒ L=2N v3C\frac{L}{2}\cdot\frac{L}{2N} = \frac{v^3}{C} \ \Rightarrow\ L = 2\sqrt{\frac{N\,v^3}{C}}

The minimum radius from comfort (at the middle of the curve):

Rmin=L2N=v3C NR_{min} = \frac{L}{2N} = \sqrt{\frac{v^3}{C\,N}}

Here, N=∣g1−g2∣N = |g_1 - g_2| as a ratio and v=V/3.6v = V/3.6.

2. Night visibility (headlight) criterion

Let the headlight height above the road be hh and the upward beam angle α\alpha (usually h=0.75h = 0.75 m, α=1∘\alpha = 1^\circ). The driver must be able to see up to the stopping distance SS. The curve is a parabola with R=L/NR = L/N.

Case (i): L>SL > S. The beam meets the road at distance SS from the vehicle, where the curve is at height yy above the tangent:

h+Stan⁡α=NS22L ⇒ L=NS22 (h+Stan⁡α)h + S\tan\alpha = \frac{N S^2}{2L} \ \Rightarrow\ L = \frac{N S^2}{2\,(h + S\tan\alpha)}

Radius: R=LN=S22(h+Stan⁡α)R = \dfrac{L}{N} = \dfrac{S^2}{2(h + S\tan\alpha)}.

Case (ii): L<SL < S.

L=2S−2 (h+Stan⁡α)N,R=LN=2SN−2 (h+Stan⁡α)N2L = 2S - \frac{2\,(h + S\tan\alpha)}{N},\qquad R = \frac{L}{N} = \frac{2S}{N} - \frac{2\,(h + S\tan\alpha)}{N^2}

Design

Find LL from the comfort and headlight criteria and adopt the greater. Then check that the radius provided is not less than the minimum radius from each criterion.

✓ Answer checked by Claude Opus 5.5 (high effort)

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