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Deflection control, sufficient stiffness method

Short answer

Deflection controlled by limiting span/effective depth ratio per IS 456 cl. 23.2.1. Basic l/d: cantilever 7, simply supported 20, continuous 26. Modified by factors kt (tension steel), kc (compression steel), kf (flanged beams). Permissible l/d = basic × kt × kc × kf. For spans >10m, basic value multiplied by 10/span. Actual l/d must not exceed permissible.

Explain how the deflection of an RC flexural member is controlled by the empirical (sufficient stiffness) method as per IS 456.

Idea of the method

Calculating the actual deflection takes a long time, so IS 456 cl. 23.2.1 allows deflection to be controlled indirectly. If the ratio of span to effective depth of a beam, slab or cantilever does not exceed a permitted value, the deflection will be within the limits of cl. 23.2 (final deflection including creep, shrinkage and temperature ≤span/250\le \text{span}/250, and the part occurring after finishes are applied ≤span/350\le \text{span}/350 or 20 mm, whichever is less). This is the empirical, or sufficient stiffness (span/depth ratio), method.

Procedure

  1. Take the basic span/effective depth ratio:
MemberBasic l/dl/d
Cantilever7
Simply supported20
Continuous26
  1. Modify it by factors:
    • ktk_t: modification factor for tension steel from Fig. 4 of IS 456, which depends on ptp_t and the service stress fs=0.58fyAst,reqAst,provf_s = 0.58 f_y \dfrac{A_{st,req}}{A_{st,prov}}. Less steel and a lower stress give a larger factor (up to 2.0).
    • kck_c: modification factor for compression steel from Fig. 5, based on pc=100Asc/bdp_c = 100A_{sc}/bd (maximum 1.5).
    • kfk_f: reduction factor for flanged beams from Fig. 6, based on the ratio bw/bfb_w/b_f only (0.8 when bw/bf≤0.3b_w/b_f \le 0.3). For flanged beams, ptp_t and pcp_c for Figs. 4 and 5 are worked out on the area bfdb_f d.
  2. For spans above 10 m (other than cantilevers), the basic value is multiplied by 10/span (m)10/\text{span (m)}; for cantilevers longer than 10 m, deflection must be calculated.
  3. The permissible ratio is
(ld)perm=(ld)basic×kt×kc×kf\left(\frac{l}{d}\right)_{perm} = \left(\frac{l}{d}\right)_{basic} \times k_t \times k_c \times k_f
  1. Compare it with the actual l/dl/d. If actual ≤\le permissible, deflection is satisfied; if not, increase dd (or the steel) and check again.

Notes

  • For two-way slabs, the check is made on the shorter span.
  • This method is a conservative approximation of Annex C (the detailed method, which adds short-term, creep and shrinkage deflections).

✓ Answer checked by Claude Opus 5.5 (high effort)

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