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Max height of straight draft tube (Francis)

Short answer

Specific speed Ns = 120√11760 / 25^1.25 = 232.8; Thoma coefficient σ = 0.0432(232.8/100)² = 0.234. Maximum draft tube height above tailwater Hs = 10 − 0.20 − 0.234×25 = 3.95 m.

A Francis turbine works under a head of 25 m and produces 11760 kW while running at 120 rpm. The turbine has been installed at a station where atmospheric pressure is 10 m of water and vapour pressure is 0.20 m of water. Calculate the maximum height of the straight draft tube for the turbine.

Data

H=25H = 25 m, P=11,760P = 11{,}760 kW, N=120N = 120 rpm, Hatm=10H_{atm} = 10 m, Hv=0.20H_v = 0.20 m.

Specific speed

Ns=NPH5/4=12011760251.25=232.8N_s = \frac{N\sqrt{P}}{H^{5/4}} = \frac{120\sqrt{11760}}{25^{1.25}} = 232.8

Thoma cavitation coefficient

σc=0.0432(Ns100)2=0.0432×(2.328)2=0.2341\sigma_c = 0.0432\left(\frac{N_s}{100}\right)^2 = 0.0432 \times (2.328)^2 = 0.2341

Maximum height (setting) of the draft tube

The maximum height of the runner outlet / draft tube inlet above the tailwater level is

Hs=Hatm−Hv−σcH=10−0.20−0.2341×25=3.95 mH_s = H_{atm} - H_v - \sigma_c H = 10 - 0.20 - 0.2341 \times 25 = 3.95\ \text{m}

Answer: the straight draft tube may be set at most about 3.95 m above the tailwater level (a lower setting is safer).

✓ Answer checked by Claude Opus 5.5 (high effort)

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