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Compare HVAC and HVDC; 2/3 power loss

Short answer

HVAC uses 3-phase, has stability limits, skin effect, and requires reactive compensation; HVDC uses 2 conductors, has no stability limit, and no reactive power in line. For same power, conductor, and insulation, AC power factor 0.943 gives equal capacity. DC line loss is 2I²R vs AC 3I²R, so HVDC loss is 2/3 of HVAC loss.

Compare AC transmission over HVDC transmission. Justify that total power loss in HVDC is only 2/3th of total power loss in HVAC transmission lines.

HVAC transmission sends power as three-phase AC through transformers; HVDC converts AC to DC at the sending end (rectifier), transmits DC, and converts back to AC (inverter). Each is best in a different range.

Comparison of AC and DC transmission

PointHVACHVDC
Conductors3 (3-phase)2 (bipolar), 1 (monopolar)
Stability limitYes, P∝sin⁡δ/XP \propto \sin\delta / XNone
Reactive powerCharging current, needs compensationNone in line
Skin effect / coronaPresent / moreAbsent / less
Terminal costLow (transformers)High (converters, filters)
Line cost per kmHighLow
InterconnectionSynchronous onlyAsynchronous possible
Fault currentHighLimited by converter control
Voltage changeEasy (transformer)Needs converter
HarmonicsLittleConverter harmonics, filters needed

AC is cheaper for short and medium distances because terminals are simple; DC is cheaper for long distances (beyond the break-even distance) and for long cables.

Justification of the 2/3 loss

Assumptions: same power capacity, same conductor size and current II, same loss per conductor p=I2Rp = I^2R, same insulation (peak voltage to earth VmV_m, with Vd=VmV_d = V_m).

Same capacity:

Pac=3⋅Vm2⋅Icos⁡ϕ=2.121 VmIcos⁡ϕPdc=2VmI\begin{aligned} P_{ac} &= 3\cdot\frac{V_m}{\sqrt{2}}\cdot I\cos\phi = 2.121\,V_mI\cos\phi \\ P_{dc} &= 2V_mI \end{aligned}

These are equal for cos⁡ϕ=0.943\cos\phi = 0.943, so a 2-conductor bipolar DC line has the same capacity as a 3-conductor AC line.

Total losses:

LossdcLossac=2I2R3I2R=2p3p=23\frac{\text{Loss}_{dc}}{\text{Loss}_{ac}} = \frac{2I^2R}{3I^2R} = \frac{2p}{3p} = \frac{2}{3}

Hence the HVDC line loss is only 2/3 of the HVAC line loss for the same power. In practice the saving is a little more, because the AC resistance is higher due to skin effect and AC lines have more corona loss.

✓ Answer checked by Claude Opus 5.5 (high effort)

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