Skip to main content

Diode reverse recovery characteristics

Short answer

Reverse recovery occurs when a conducting diode is switched to reverse bias: stored minority carriers cause a reverse current flow for a time trr, with peak Irr, before the diode blocks. This stored charge leads to switching losses and voltage spikes, requiring fast-recovery or Schottky diodes to minimize effects.

Explain the reverse recovery characteristics of diode.

Reverse recovery: when a conducting diode is switched to reverse bias, its current does not stop at zero. The minority carriers stored in the junction must first be removed, so the current falls through zero, flows in the reverse direction for a short time and then decays to zero.

  iD
   ^ IF
   |-------.
   |        \  slope = di/dt
   |         \
 --+----------\--------------------> t
   |           \      .--------
   |            \   .'
   |   - IRR ....\.'   tb
   |          ta  |<->|
   |         |<-->|
   |         |<---trr--->|
  • tat_a: time from current zero to the peak reverse current IRRI_{RR}, while charge stored in the depletion region is removed.
  • tbt_b: time for the reverse current to decay from IRRI_{RR} to about 0.25IRR0.25 I_{RR}, while charge in the bulk is removed.
  • Reverse recovery time trr=ta+tbt_{rr} = t_a + t_b; softness factor S=tb/taS = t_b / t_a.
  • Peak reverse current: IRR=tadidtI_{RR} = t_a \dfrac{di}{dt}.
  • Reverse recovery (stored) charge QRRQ_{RR} is the area under the reverse current, approximately a triangle:
QRR=12IRR trrQ_{RR} = \tfrac{1}{2} I_{RR}\, t_{rr}

Soft and abrupt recovery

PointSoft recoveryAbrupt (fast) recovery
Softness S=tb/taS = t_b/t_aAbout 1Much less than 1
Reverse current decayGradualSharp (snap-off)
Voltage spikes and EMISmallLarge, with oscillation
UsesGeneral purpose, inductive circuitsHigh-frequency choppers and inverters

Effects of reverse recovery

  • Extra switching loss ≈VRQRRf\approx V_R Q_{RR} f.
  • Over-voltage spikes L di/dtL\,di/dt in stray inductances.
  • In bridge circuits, the recovering diode draws a current spike through the incoming switch.

Hence power circuits use fast recovery or Schottky diodes, which have small trrt_{rr} (a few µs down to ns).

✓ Answer checked by Claude Opus 5.5 (high effort)

All Power Electronics chapter 1 questions →