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Power diode V-I and reverse recovery

Short answer

A power diode is a P-i-N device with low forward drop and reverse blocking up to the breakdown voltage. Reverse recovery occurs at turn-off: stored minority carriers cause a reverse current peak before blocking resumes, characterized by recovery time trr and stored charge Qrr.

Explain the working of power diode with the help of V-I curve. What do you mean by reverse recovery characteristic of a power diode?

A power diode is a two-terminal P-N junction (with a lightly doped n−n^- drift layer, the P-i-N structure) that conducts when its anode is positive with respect to the cathode and blocks when reverse biased. It is designed for large current and high reverse voltage.

Structure

   Anode
     |
   [ p+ ]   heavily doped
   [ n- ]   drift region (sets
   [    ]   reverse voltage rating)
   [ n+ ]   substrate
     |
   Cathode

V-I characteristic

              iD
               ^         /  forward
               |        /   conduction
               |       /
               |      /
     -VRRM     |    _/ slope 1/r
  ----+--------+---'--------------> vD
      |   reverse    Vcut-in
      |   leakage    (0.7-1 V)
      |   (very small)
      |
      v reverse breakdown (avalanche)
  • Forward bias: after the cut-in voltage (about 0.7 to 1 V), the current rises rapidly. The forward drop at rated current is about 1 to 2 V because of the drift-region resistance (on-state resistance rr).
  • Reverse bias: only a small leakage current (µA to mA) flows until the reverse breakdown voltage VBRV_{BR}. The diode is rated for a repetitive peak reverse voltage VRRMV_{RRM} below this. Beyond breakdown, avalanche current flows and the diode may be damaged.

Reverse recovery characteristic

Reverse recovery: when a conducting diode is switched to reverse bias, its current does not stop at zero. The minority carriers stored in the junction must first be removed, so the current falls through zero, flows in the reverse direction for a short time and then decays to zero.

  iD
   ^ IF
   |-------.
   |        \  slope = di/dt
   |         \
 --+----------\--------------------> t
   |           \      .--------
   |            \   .'
   |   - IRR ....\.'   tb
   |          ta  |<->|
   |         |<-->|
   |         |<---trr--->|
  • tat_a: time from current zero to the peak reverse current IRRI_{RR}, while charge stored in the depletion region is removed.
  • tbt_b: time for the reverse current to decay from IRRI_{RR} to about 0.25IRR0.25 I_{RR}, while charge in the bulk is removed.
  • Reverse recovery time trr=ta+tbt_{rr} = t_a + t_b; softness factor S=tb/taS = t_b / t_a.
  • Peak reverse current: IRR=tadidtI_{RR} = t_a \dfrac{di}{dt}.
  • Reverse recovery (stored) charge QRRQ_{RR} is the area under the reverse current, approximately a triangle:
QRR=12IRR trrQ_{RR} = \tfrac{1}{2} I_{RR}\, t_{rr}

Depending on SS, diodes are soft recovery (S≈1S \approx 1, less oscillation) or fast/abrupt recovery (small SS). Reverse recovery causes extra switching loss and voltage spikes, so fast-recovery diodes are used in choppers and inverters.

✓ Answer checked by Claude Opus 5.5 (high effort)

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