- 2073 Bhadra · 10 marks
FET amplifier design flow and conditional stability
Short answer
Design flow: specify, bias FET, get S-parameters, compute Δ and K; if K<1 draw stability circles and select Γs, ΓL in stable region, then design matching. Conditional stability means K<1, so only some loads are safe. Example: K=0.607, source circle CS=1.132∠68.46°, RS=0.199; stable region outside circles.
Show a flow diagram that explains designing of an amplifier using a FET transistor. With self-defined parameters and the help of a smith chart define conditional stability of a microwave amplifier.
Flow diagram for FET amplifier design
+------------------------------+
| Specs: f, gain, Z0, BW, NF |
+------------------------------+
|
+------------------------------+
| Choose transistor, bias; |
| get [S] at design frequency |
+------------------------------+
|
+------------------------------+
| Compute Δ, K (and μ) |
+------------------------------+
|
K>1 and |Δ|<1 ?
yes | | no
v v
Uncond. stable Draw stability circles;
| pick Γs, ΓL in stable
| region (or stabilise)
+----+-----+
|
Unilateral? (U small, S12≈0)
yes: Γs=S11*, ΓL=S22*
no : Γs=ΓMS, ΓL=ΓML (bilateral)
|
+------------------------------+
| Compute GS, G0, GL -> GT |
+------------------------------+
|
+------------------------------+
| Design input/output matching |
| (stubs or L-C) on Smith chart|
+------------------------------+
|
| Bias network, layout, simulate
|
Specs met? -- no --> revise
| yes
Build & test
Notes: the FET is biased (e.g. VDS, IDS from the datasheet) before reading [S]; matching networks transform 50 Ω to the required Γs and ΓL; RF chokes and DC blocks isolate bias from RF.
Conditional stability
An amplifier is conditionally (potentially) stable if |Γin| > 1 or |Γout| > 1 for some passive source or load. It happens when K < 1 (or |Δ| > 1). Then only certain Γs and ΓL are allowed, and these are found with stability circles.
Self-defined example
Assume a GaAs FET with S11 = 0.894∠−60.6°, S12 = 0.020∠62.4°, S21 = 3.122∠123.6°, S22 = 0.781∠−27.6°.
Δ = 0.6964∠−83.07°, K = 0.607 < 1
→ conditionally stable
Output (load) circle: CL = 1.363∠46.69°, RL = 0.500
Input (source) circle: CS = 1.132∠68.46°, RS = 0.199
Using the Smith chart
- Plot CL with radius RL on the ΓL plane and CS with radius RS on the Γs plane.
- Test the centre: for ΓL = 0, |Γin| = |S11| = 0.894 < 1, and for Γs = 0, |Γout| = |S22| = 0.781 < 1, so the centre is stable in both planes. The centre is outside both circles, so the stable region is outside the circles.
- The parts of the circles that fall inside the unit chart (near the top-right, inductive high-|Γ| region) are the unstable regions; Γs and ΓL must not be placed there.
.-----------.
/ (###) ### = unstable
| o (##) region (inside
| centre circle and chart)
| stable |
\ /
'-----------'
- Select Γs, ΓL in the stable region with some margin and check |Γin| < 1 and |Γout| < 1. For Γs = S11*, ΓL = S22*: |Γin| = 0.912, |Γout| = 0.848, so this choice is stable and gives GTU,max = 20.95 dB (unilateral estimate; the actual GT is 20.06 dB).
- If the desired point is unstable, add resistive loading (series/shunt resistor at input or output) or feedback to make the FET stable.
✓ Answer checked by Claude Opus 5.5 (high effort)
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