- 2082 Baisakh · 4+4+2 marks
Hybrid tee with terminated arms
Short answer
With E-arm matched, H-arm input divides equally in phase to collinear ports; with H-arm terminated, E-arm input divides equally 180 degrees out of phase. With collinear arms terminated, E and H arms are matched and isolated, enabling balanced mixers and bridge measurements.
Using proper S-Matrices, mention the properties of a Hybrid-Tee in the situation of (a) terminated E-arm, (b) terminated H-arm and (c) terminated co-planar arms.
For an ideal hybrid (magic) tee with ports 1 and 2 collinear, port 3 the H-arm and port 4 the E-arm:
| 0 0 1 1 |
[S] = (1/√2) | 0 0 1 -1 |
| 1 1 0 0 |
| 1 -1 0 0 |
When a port is terminated in a matched load, no wave returns into it (aₖ = 0), so its column is dropped; its row tells how much power the load absorbs. The remaining matrix describes the reduced network.
(a) E-arm (port 4) terminated in a matched load
Remaining ports 1, 2, 3:
| 0 0 1 |
[S] = (1/√2) | 0 0 1 |
| 1 1 0 |
- Input at H-arm (3) divides equally and in phase to ports 1 and 2: the device works as an H-plane (in-phase) power divider.
- Input at port 1: half the power goes to port 3, half (b4 = a1/√2) is absorbed in the E-arm load; port 2 receives nothing.
- In-phase equal inputs at 1 and 2 combine fully at port 3 (power combiner); any imbalance goes to the load.
(b) H-arm (port 3) terminated in a matched load
Remaining ports 1, 2, 4:
| 0 0 1 |
[S] = (1/√2) | 0 0 -1 |
| 1 -1 0 |
- Input at E-arm (4) divides equally to ports 1 and 2 but 180° out of phase: it works as an E-plane (anti-phase) divider.
- Input at port 1: half goes to port 4, half is absorbed in the H-arm load; ports 1 and 2 remain isolated.
- Anti-phase equal inputs at 1 and 2 combine fully at port 4.
(c) Co-planar (collinear) arms 1 and 2 terminated in matched loads
Remaining ports 3 and 4:
| S33 S34 | | 0 0 |
[S] = | | = | |
| S43 S44 | | 0 0 |
- Both E and H arms are matched (no reflection) and completely isolated from each other (S34 = 0).
- Power fed into either the E-arm or the H-arm is split equally into the two loads and fully absorbed.
- This isolation between E and H arms is the basis of the balanced mixer (LO at one arm, signal at the other) and of bridge measurements: with identical loads on 1 and 2, no signal passes from H-arm to E-arm; any mismatch difference between the two loads shows up at the E-arm.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Three-port model and magic tee with shorted arms · RF and Microwave Engineering, chapter 4
- S-matrices of E-plane tee, H-plane tee and duplexer · RF and Microwave Engineering, chapter 4
- Two magic tees connected at E-arms · RF and Microwave Engineering, chapter 4
- Why insertion loss; double-section shunt-arm LPF · RF and Microwave Engineering, chapter 6
- Properties of stiffness and flexibility matrices · Theory of Structures II, chapter 2
- Proper vs improper handoff; cellular concept N = 7 · Wireless Communication, chapter 2
- Voltage ratio transfer function, port 2 terminated by 2 H · Electrical Circuit Theory, chapter 5
- G21 and α21 of two-port terminated in 2 Ω · Electrical Circuit Theory, chapter 5