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Annual cost and saving with pf correction (400 kVA)

Short answer

Annual cost at 0.7 pf: Rs 323,000. Required capacitor Qc = 280(1.0202−0.4843) = 150.05 kVAR. With yearly demand charge, MD saving Rs 10,667, corrector annual cost Rs 15,005, net loss Rs 4,338; not economical.

An industry consumes 50000 units of electricity in a year at average power factor of 0.7 lag. The recorded max. demand is 400 kVA. The tariff is Rs. 120/kVA plus Rs. 5.50 per kWhr. Calculate the annual cost of supply and find out annual saving in cost by installing power factor improving device costing Rs. 1000 per kVAR which raises the power factor from 0.7 to 0.9 lagging. Allow 10% per year on the cost of the improving device to cover all additional cost.

Given: energy 50,000 kWh/year, pf 0.7 lag, maximum demand 400 kVA, tariff Rs 120/kVA + Rs 5.50/kWh, corrector Rs 1000/kVAR, annual charges 10%, pf raised to 0.9. The demand charge is taken per kVA per year, as printed.

Annual cost of supply at pf 0.7

MD charge=400×120=Rs 48 000Energy charge=50 000×5.50=Rs 275 000Annual cost=Rs 323 000\begin{aligned} \text{MD charge} &= 400 \times 120 = \text{Rs } 48\,000 \\ \text{Energy charge} &= 50\,000 \times 5.50 = \text{Rs } 275\,000 \\ \text{Annual cost} &= \text{Rs } 323\,000 \end{aligned}

Corrector rating

Maximum-demand kW =400×0.7=280= 400 \times 0.7 = 280 kW.

QC=280(tan⁡ϕ1−tan⁡ϕ2)=280(1.0202−0.4843)=150.05 kVARCost=150.05×1000=Rs 150 047Annual charge=0.10×150 047=Rs 15 005\begin{aligned} Q_C &= 280(\tan\phi_1 - \tan\phi_2) = 280(1.0202 - 0.4843) = 150.05\ \text{kVAR} \\ \text{Cost} &= 150.05 \times 1000 = \text{Rs } 150\,047 \\ \text{Annual charge} &= 0.10 \times 150\,047 = \text{Rs } 15\,005 \end{aligned}

New demand and saving

S2=2800.9=311.11 kVAReduction in MD charge=(400−311.11)×120=Rs 10 667Net annual saving=10 667−15 005=−Rs 4 338\begin{aligned} S_2 &= \frac{280}{0.9} = 311.11\ \text{kVA} \\ \text{Reduction in MD charge} &= (400 - 311.11) \times 120 = \text{Rs } 10\,667 \\ \text{Net annual saving} &= 10\,667 - 15\,005 = -\text{Rs } 4\,338 \end{aligned}

The energy charge (kWh) does not change. With the demand charge per year, the device costs more than it saves (net loss of Rs 4,338), so it is not economical.

If the demand charge is Rs 120/kVA per month

This is the usual way demand is billed (e.g. NEA bills demand monthly):

Annual cost=400×120×12+275 000=Rs 851 000MD saving=88.89×1440=Rs 128 000Net saving=128 000−15 005=Rs 112 995\begin{aligned} \text{Annual cost} &= 400 \times 120 \times 12 + 275\,000 = \text{Rs } 851\,000 \\ \text{MD saving} &= 88.89 \times 1440 = \text{Rs } 128\,000 \\ \text{Net saving} &= 128\,000 - 15\,005 = \text{Rs } 112\,995 \end{aligned}

Answer: Annual cost Rs 323,000; corrector 150.05 kVAR costing Rs 150,047. On a yearly demand charge the net saving is −Rs 4,338 (a loss). On a monthly demand charge the annual cost is Rs 851,000 and the net saving is about Rs 112,995 per year.

✓ Answer checked by Claude Opus 5.5 (high effort)

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