- 2081 Baisakh · 8 marks
Annual cost and saving with pf correction (400 kVA)
Short answer
Annual cost at 0.7 pf: Rs 323,000. Required capacitor Qc = 280(1.0202−0.4843) = 150.05 kVAR. With yearly demand charge, MD saving Rs 10,667, corrector annual cost Rs 15,005, net loss Rs 4,338; not economical.
An industry consumes 50000 units of electricity in a year at average power factor of 0.7 lag. The recorded max. demand is 400 kVA. The tariff is Rs. 120/kVA plus Rs. 5.50 per kWhr. Calculate the annual cost of supply and find out annual saving in cost by installing power factor improving device costing Rs. 1000 per kVAR which raises the power factor from 0.7 to 0.9 lagging. Allow 10% per year on the cost of the improving device to cover all additional cost.
Given: energy 50,000 kWh/year, pf 0.7 lag, maximum demand 400 kVA, tariff Rs 120/kVA + Rs 5.50/kWh, corrector Rs 1000/kVAR, annual charges 10%, pf raised to 0.9. The demand charge is taken per kVA per year, as printed.
Annual cost of supply at pf 0.7
Corrector rating
Maximum-demand kW kW.
New demand and saving
The energy charge (kWh) does not change. With the demand charge per year, the device costs more than it saves (net loss of Rs 4,338), so it is not economical.
If the demand charge is Rs 120/kVA per month
This is the usual way demand is billed (e.g. NEA bills demand monthly):
Answer: Annual cost Rs 323,000; corrector 150.05 kVAR costing Rs 150,047. On a yearly demand charge the net saving is −Rs 4,338 (a loss). On a monthly demand charge the annual cost is Rs 851,000 and the net saving is about Rs 112,995 per year.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Annual charge and pf improvement (Rs 1300/kVA tariff) · Utilization of Electrical Energy, chapter 6 · asked 3×
- Annual charge and pf improvement (Rs 65/kVA tariff) · Utilization of Electrical Energy, chapter 6 · asked 3×
- Annual charge and pf improvement for 1200 kVA load · Utilization of Electrical Energy, chapter 6 · asked 3×
- Annual saving by pf improvement for 800 kW load · Utilization of Electrical Energy, chapter 6
- Annual saving by capacitors for 200 kW factory · Utilization of Electrical Energy, chapter 6
- HV vs LV supply tariff for a factory · Utilization of Electrical Energy, chapter 6 · asked 2×
- Optimum pf under two-part tariff (200 kW) · Industrial Power Distribution and Illumination, chapter 10
- PF correction for 1250 kVA generator (+170 kW) · Industrial Power Distribution and Illumination, chapter 10
- Energy and cost saving from lighting retrofit · Industrial Power Distribution and Illumination, chapter 10
- Most economical power factor for 50 kW factory · Industrial Power Distribution and Illumination, chapter 10