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Numerical: co-channel distance for 7-cell reuse

Short answer

Cell radius from hexagon area 23 km² is R=√(23/2.598)=2.975 km. With N=7, reuse ratio is √21=4.583, so the minimum co-channel distance is D=4.583×2.975=13.63 km.

For a seven cell reuse pattern, find the minimum distance between centers of co-channel cells. Area of each cell is uniform and is equal to 23 square km.

Given: N = 7, area of each hexagonal cell = 23 km².

Step 1: Cell radius from hexagon area

A = (3√3/2) R² = 2.598 R²
R² = 23 / 2.598 = 8.853
R  = 2.975 km

Step 2: Co-channel reuse ratio

Q = √(3N) = √21 = 4.583

Step 3: Minimum co-channel distance

D = Q × R = 4.583 × 2.975 = 13.63 km

Answer: The minimum distance between centres of co-channel cells is about 13.63 km.

✓ Answer checked by Claude Opus 5.5 (high effort)

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