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Improper earthing and unsafe step/touch potential

Short answer

Fault current raises the ground to GPR=IgRg, producing dangerous voltages. Touch potential is between hand on earthed metal and feet 1 m away, with body current Etouch/(Rb+1.5ρs); step potential is between feet 1 m apart, with Estep/(Rb+6ρs). Safe IEEE 80 limits are (1000+1.5Csρs)0.116/√t and (1000+6Csρs)0.116/√t; high Rg, wide mesh and no surface layer make them unsafe.

Explain how Improper Earthing may result in step potential and touch potential beyond safe value in power system with necessary diagram and formulae.

When an earth fault occurs, fault current IgI_g enters the soil through the earth electrode or substation grid. The grid rises to the ground potential rise

GPR=IgRgGPR = I_g R_g

and the ground surface potential falls with distance from the electrode. A person bridging part of this potential gets a shock. Improper earthing (high RgR_g, too few electrodes, wide mesh, no bonding, no surface layer, slow protection) makes these potentials exceed the safe values.

 V
 |\_ GPR = Ig Rg
 |  \       steep gradient
 |   \__    (poor earthing)
 |      \___
 |  Et      \____ Es
 +---|--|-----|-|------> distance
   structure  feet 1 m apart

Touch potential

Voltage between the hand on an earthed structure and the feet standing 1 m away. Equivalent circuit: body resistance RbR_b in series with two feet in parallel (Rf/2R_f/2), where Rf≈3ρsR_f \approx 3\rho_s:

Ib=EtouchRb+1.5ρsI_b = \frac{E_{touch}}{R_b + 1.5\rho_s}

Step potential

Voltage between two feet 1 m apart. Body RbR_b in series with two feet (2Rf2R_f):

Ib=EstepRb+6ρsI_b = \frac{E_{step}}{R_b + 6\rho_s}

Safe (tolerable) limits (IEEE 80, 50 kg person)

Using Dalziel's current Ib=0.116tsI_b = \frac{0.116}{\sqrt{t_s}} and Rb=1000 ΩR_b = 1000\ \Omega:

Etouch,50=(1000+1.5Csρs)0.116ts,Estep,50=(1000+6Csρs)0.116tsE_{touch,50} = (1000 + 1.5C_s\rho_s)\frac{0.116}{\sqrt{t_s}}, \qquad E_{step,50} = (1000 + 6C_s\rho_s)\frac{0.116}{\sqrt{t_s}}

CsC_s is the surface-layer derating factor and tst_s the fault duration.

How improper earthing makes them unsafe

  1. High grid resistance RgR_g: GPR =IgRg= I_gR_g is large, so actual touch voltage (a fraction of GPR) is large. For example, Ig=2I_g = 2 kA and Rg=5 ΩR_g = 5\ \Omega gives GPR = 10 kV; even 30% of this (3 kV) as touch voltage is far above the safe value of a few hundred volts.
  2. Wide mesh or no grid: surface potential is not uniform; mesh (touch) voltage
Em=ρKmKiIgLME_m = \frac{\rho K_m K_i I_g}{L_M}

rises when the total buried length LML_M is small. 3. Steep gradient at the edge (no grading ring): high step voltage

Es=ρKsKiIgLSE_s = \frac{\rho K_s K_i I_g}{L_S}
  1. No surface layer of crushed rock: low ρs\rho_s, so tolerable voltages drop.
  2. Unbonded equipment or fences: the full GPR may appear as touch voltage.
  3. High RgR_g reduces fault current so relays may be slow; longer tst_s lowers the tolerable limits.

Remedies

Lower RgR_g (more rods, larger grid, deep electrodes, chemical backfill), closer mesh spacing, bonding of all metal parts, a crushed-rock surface layer, grading rings, and fast fault clearing so that Eactual<EtolerableE_{actual} < E_{tolerable}.

✓ Answer checked by Claude Opus 5.5 (high effort)

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