How is the number of CAT6 boxes found?

100 x 35 m = 3,500 m, add 10% wastage to get 3,850 m, divide by 305 m and round up to 13

3,500 m divided by 305 m rounded down to 11

96 x 35 m divided by 100 m per box

Why are 5 patch panels needed?

100 ports divided by 24 per panel is 4.2, rounded up to 5

How are the 205 patch cords made up?

100 user-side 2 m, 100 panel-to-switch 1 m, and 5 switch-to-core 1 m

100 panel-to-switch and 105 switch-to-router

Why is an extra PoE switch included beyond the four 24-port access switches?

To power the 4 wireless APs over the cable and give spare uplink ports

To connect the router to the internet

2072 Asoj · 12 marks

BoQ for NITC four research labs

Short answer

For 96 PCs plus 4 APs, estimate 100 CAT6 drops at 35 m average, giving 3,850 m and 13 boxes. Use 100 faceplates, 5 patch panels, 4 access switches plus 1 PoE switch, and 1 core L3 switch. Assign each lab a /27 subnet from 192.168.10.0/24.

NITC building had 4 research labs each having 24 computers. All labs are located at the 1st floor. Each computer is to be connected in the network from NCR located at 2nd floor. Prepare a bill of quantity (BoQ) with necessary network resources required for complete networking. The BoQ must include estimation of all network resources required.

Assumptions

4 labs x 24 computers = 96 computers, all on the 1st floor. The Network Control Room (NCR) is on the 2nd floor, directly above.
One single-port CAT6 outlet per computer, plus 1 wireless AP per lab (4 drops). Total drops = 96 + 4 = 100.
Floor height 4 m; horizontal run about 28 m; plus slack: average cable run per drop = 35 m (under the 90 m limit).
10% wastage on cable. Cable box = 305 m. Switches are 24-port GE with SFP uplinks. The NCR also needs a router/firewall for the internet link.

Layout

 Internet
    |
 [Router/Firewall]            NCR (2nd floor)
    |
 [Core L3 switch]
    |
 [Patch panels x5]--[Switch x5 (4 + 1 PoE)]
    |
    | CAT6 (100 runs, 35 m average)
 ---+---------+---------+---------+---  1st floor
  Lab 1     Lab 2     Lab 3     Lab 4
  24 PC     24 PC     24 PC     24 PC
  + AP      + AP      + AP      + AP

Quantity estimation

Outlets (single-port faceplate with jack): 96 + 4 = 100.
Cable length: 100 x 35 = 3,500 m. With 10% wastage = 3,850 m. Boxes = 3,850 / 305 = 12.6, so 13 boxes.
Patch panel ports = 100. 100 / 24 = 4.2, so 5 patch panels (24-port).
Switches: 96 PC ports / 24 = 4 switches fully used, plus 1 PoE switch for the 4 APs and spare ports = 5 access switches. One core L3 switch connects them to the router = 1.
Patch cords: user side 2 m = 100; panel to switch 1 m = 100; switch to core 1 m = 5. Total 205.
Rack space: 5 panels (5U) + 5 switches (5U) + core (1U) + router/firewall (1U) + cable managers (4U) + UPS (2U) = 18U, so one 24U or 42U rack.

Bill of Quantity

S.N.	Item	Specification	Qty
1	CAT6 UTP cable	305 m box	13 boxes
2	Faceplate + jack	Single-port, CAT6	100
3	Patch panel	24-port CAT6	5
4	Patch cord 2 m	CAT6	100
5	Patch cord 1 m	CAT6	105
6	Access switch	24-port GE + 2 SFP	4
7	PoE switch	24-port PoE+	1
8	Core L3 switch	24-port, SFP+	1
9	Wireless AP	Dual-band, PoE	4
10	Router / firewall	NAT, DHCP	1
11	Rack	42U with cable managers	1
12	UPS	2 kVA	1
13	PVC conduit / trunking	25 mm	150 m
14	Cable ties, labels		lot
15	Cable tester		1

IP plan (192.168.10.0/24)

Network	Subnet	Usable	Gateway
Lab 1	192.168.10.0/27	30	.1
Lab 2	192.168.10.32/27	30	.33
Lab 3	192.168.10.64/27	30	.65
Lab 4	192.168.10.96/27	30	.97
Wi-Fi / APs	192.168.10.128/27	30	.129
Servers / management	192.168.10.160/27	30	.161

Each /27 has 30 usable hosts, enough for 24 PCs and a gateway with spare addresses. The core L3 switch routes between the subnets, and the router provides DHCP (through DHCP relay on the core) and NAT to the internet.

✓ Answer checked by Claude Opus 5.5 (high effort)

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