Skip to main content

Specific speed of a turbine

Short answer

Specific speed Ns is the rpm of a geometrically similar turbine producing 1 kW under 1 m head. It classifies turbines (Pelton 10-35, Francis 60-300, Kaplan 300-1000), enables model-to-prototype scaling, and guides speed selection and cavitation check.

How the 'specific speed' is defined for a turbine? Discuss its purpose.

Specific speed (NsN_s) of a turbine is the speed at which a geometrically similar model turbine would run if it produced 1 kW of power under a head of 1 m. It is a type number that describes the shape of the runner.

Derivation (outline)

For similar turbines, the jet/flow velocity varies as V∝HV \propto \sqrt{H} and the peripheral speed u=πDN/60∝Hu = \pi D N/60 \propto \sqrt{H}, so D∝H/ND \propto \sqrt{H}/N. Discharge Q∝D2HQ \propto D^2\sqrt{H} and power P∝QH∝D2H3/2P \propto QH \propto D^2 H^{3/2}. Substituting DD:

P∝HN2 H3/2=H5/2N2⇒N=K H5/4P\begin{aligned} P &\propto \frac{H}{N^2}\,H^{3/2} = \frac{H^{5/2}}{N^2} \\ \Rightarrow N &= K\,\frac{H^{5/4}}{\sqrt{P}} \end{aligned}

When P=1P = 1 kW and H=1H = 1 m, N=K=NsN = K = N_s. Hence

Ns=NPH5/4N_s = \frac{N\sqrt{P}}{H^{5/4}}

with NN in rpm, PP in kW and HH in m.

Purpose

  1. Selection of turbine type: each type works best in a band of NsN_s:
TurbineNsN_s range (kW, m)
Pelton (single jet)10–35
Pelton (multi jet)35–60
Francis60–300
Kaplan / propeller300–1000
  1. Comparison of turbines: turbines of different size are compared on one scale.
  2. Model testing: a model and prototype with the same NsN_s are geometrically and dynamically similar, so model results can be scaled up.
  3. Fixing speed and unit size: for a given head and power, choosing NsN_s fixes the rotational speed, and hence the generator poles and cost.
  4. Cavitation check: the Thoma critical σ\sigma rises with NsN_s, so NsN_s fixes how low the runner must be set.

Example: N=600N = 600 rpm, P=5000P = 5000 kW, H=200H = 200 m gives Ns=6005000/2001.25≈56.4N_s = 600\sqrt{5000}/200^{1.25} \approx 56.4, which lies at the boundary of multi-jet Pelton and slow Francis, so both would be compared.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Power Plant Design chapter 3 questions →