- 2080 Baisakh · 3 marks
Talker and listener echo in four-wire circuit
Short answer
Four-wire loss L = S – B = 0 dB. Talker echo attenuation = 6 + L + B + L + 6 = 15 dB; delay = round-trip 20 ms + 2×1 ms = 22 ms. Listener echo attenuation relative to direct signal = 2S = 6 dB.
A four-wire circuit has a round-trip delay of 20 milliseconds. The propagation time for the two-wire circuit connected to each end is 1 millisecond, and its attenuation is 6 dB. The balance return loss is 3 dB and the stability margin is 3 dB. Calculate the attenuation of the talker echo, delay of talker echo, and attenuation of listener echo.
Assumptions (standard four-wire model): = overall loss of the four-wire circuit between its two-wire terminals (hybrid to hybrid), = balance return loss of each hybrid, stability margin (half the loss round the four-wire loop). Each subscriber is joined to a hybrid by a two-wire circuit of 6 dB loss and 1 ms delay.
Four-wire loss
Talker─[2W: 6dB,1ms]─H1══ 4-wire (L) ══H2─[2W]─Listener
^ │ reflects (B)
└──────── talker echo <─────────┘
Talker echo (talker's speech reflected at the far hybrid and heard by the talker):
Listener echo (signal reflected at the far hybrid, then again at the near hybrid, reaching the listener late). Compared with the direct signal it travels once more round the four-wire loop:
(absolute: dB from talker to listener, against 12 dB for the direct signal), delayed by 20 ms relative to it.
Answer: talker echo attenuation = 15 dB, talker echo delay = 22 ms, listener echo attenuation = 6 dB (relative to the received speech, i.e. 18 dB overall).
✓ Answer checked by Claude Opus 5.5 (high effort)
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