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T/F: interconnection decreases SCMVA

Short answer

False. Interconnection adds parallel fault-current paths, reducing Thevenin impedance, so short-circuit MVA increases. SCMVA = base MVA / Z_th pu, and lower Z_th raises fault level.

State and justify whether the following statement is true or false: Interconnected system decreases SCMVA of the connected bus.

FALSE. Interconnection increases the short-circuit MVA (SCMVA) of the buses that are connected.

Justification

  • The short-circuit MVA at a bus is
SCMVA=MVAbaseZth (pu)SCMVA = \frac{MVA_{base}}{Z_{th}\ (\text{pu})}

where ZthZ_{th} is the Thevenin impedance seen from the faulted bus.

  • When a bus is tied to another system, the second system's generators feed the fault through the tie line. The tie path is in parallel with the existing source impedance, so ZthZ_{th} becomes smaller.
  • Smaller ZthZ_{th} means larger fault current and larger SCMVA.

Example: a bus with Zth=0.2Z_{th} = 0.2 pu (100 MVA base) has SCMVA =500= 500 MVA. If an interconnection adds a parallel path of 0.30.3 pu, then Zth=(0.2×0.3)/(0.5)=0.12Z_{th} = (0.2 \times 0.3)/(0.5) = 0.12 pu and SCMVA =833= 833 MVA.

Consequences

  • Circuit breakers and switchgear at the connected buses may need higher breaking capacity.
  • A higher SCMVA is also good: the bus becomes a "stiffer" source, so voltage dips and flicker during load changes are smaller.
  • Fault levels can be limited by series reactors, high-impedance transformers or HVDC links (which do not add fault current).

✓ Answer checked by Claude Opus 5.5 (high effort)

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