- 2071 Chaitra · 4 marks
Suppressing disturbance by increasing G(s) or H(s)
Short answer
Disturbance output is C_D = [G2/(1+G1G2H)]D; for large loop gain it approximates D/(G1H). Increasing G1 and/or H reduces this, suppressing disturbance, provided the system remains stable.
Effect of disturbance in case of feedback control system can be suppressed by increasing the gain G(s) and/or H(s). Justify.
The statement is justified, provided that the gain increased is the one in the loop before the point where the disturbance enters, and that the system stays stable.
Let the disturbance enter between (controller) and (plant), with feedback .
R + +----+ + +----+ C
-->(Σ)--->| G1 |-->(Σ)->| G2 |--+-->
^ - +----+ ^ D +----+ |
| +----+ |
+-------| H |<-------------+
+----+
With (superposition), the output due to the disturbance is
For large loop gain, :
So increasing and/or makes smaller, and the disturbance is suppressed. In open loop, , with no reduction at all.
Output due to the reference: , which is almost independent of the gains, so tracking is not harmed.
Limits
- Raising alone does not help much: the result tends to , which does not depend on .
- Raising also lowers the closed-loop gain (), so it must be chosen with the required output level in mind.
- Very high gain can reduce damping or cause instability in higher-order systems, and it amplifies sensor noise.
✓ Answer checked by Claude Opus 5.5 (high effort)
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