- 2076 Chaitra · 4 marks
Band bending in semiconductors
Short answer
Band bending is the spatial variation of energy bands (E_c, E_v) due to electric fields. In equilibrium, the Fermi level stays flat; doping or junctions create built-in potentials, so bands curve by e times the potential difference while the bandgap remains constant.
Explain how does the band bends in semiconductor.
Band bending is the curving of the energy bands (, , ) with position inside a semiconductor. It happens wherever there is an electric field, i.e. wherever the electrostatic potential changes with position.
Why the bands bend
The energy of an electron at a point is its band energy plus its potential energy :
The field is , so
- Where the bands are flat.
- Where a field exists, all three levels shift by the same amount, so the band gap stays constant but the bands tilt or curve.
- An electron "rolls down" the conduction band and a hole "floats up" the valence band.
Common cases
- Applied voltage on a uniform bar: the field is uniform, so the bands tilt in a straight line. The Fermi level is no longer flat; current flows.
- pn junction (equilibrium): electrons diffuse to the p side and holes to the n side, leaving fixed ion charges. These create a built-in field. Because the Fermi level must be the same throughout in equilibrium, the bands bend in the depletion region by .
- Non-uniform doping, metal–semiconductor contact, surface charges: each creates a local space charge and field, so the bands bend near that region.
p side n side
Ec ----\
\__________ Ec
EF ------------------- EF (flat)
Ev ----\
\__________ Ev
|<-W->| depletion region
bending = eV0
Key rule
In equilibrium the Fermi level is flat; any difference in doping is accommodated by bending of and . The amount of bending equals times the potential difference across the region.
✓ Answer checked by Claude Opus 5.5 (high effort)
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