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Intrinsic concentration and its temperature dependence

Short answer

Intrinsic concentration ni = √(Nc Nv) exp(-Eg/2kT), with Nc, Nv ∝ T^(3/2). ni increases rapidly with temperature due to the exponential term; a semilog plot of ni vs 1/T yields slope -Eg/2k. Resistance falls sharply (negative temperature coefficient).

Derive the relation for intrinsic concentration and explain how temperature effects intrinsic concentration with necessary diagram.

Intrinsic concentration nin_i is the number of electrons per unit volume in the conduction band (equal to the number of holes in the valence band) of a pure semiconductor at temperature TT.

Electron concentration in the conduction band

The number of electrons is the density of states gc(E)g_c(E) times the probability of occupancy f(E)f(E), integrated over the band:

n=∫Ec∞gc(E) f(E) dE,gc(E)=82 π me∗3/2h3E−Ecn = \int_{E_c}^{\infty} g_c(E)\, f(E)\, dE, \qquad g_c(E) = \frac{8\sqrt{2}\,\pi\, m_e^{*3/2}}{h^3}\sqrt{E-E_c}

For E−EF≫kTE - E_F \gg kT (non-degenerate case), f(E)≈exp⁡[−(E−EF)/kT]f(E) \approx \exp[-(E-E_F)/kT] (Boltzmann approximation). Integrating gives

n=Ncexp⁡[−Ec−EFkT],Nc=2(2πme∗kTh2)3/2n = N_c \exp\left[-\frac{E_c - E_F}{kT}\right], \qquad N_c = 2\left(\frac{2\pi m_e^* kT}{h^2}\right)^{3/2}

where NcN_c is the effective density of states at the conduction band edge.

Hole concentration in the valence band

In the same way, using 1−f(E)1 - f(E) as the probability that a state is empty:

p=Nvexp⁡[−EF−EvkT],Nv=2(2πmh∗kTh2)3/2p = N_v \exp\left[-\frac{E_F - E_v}{kT}\right], \qquad N_v = 2\left(\frac{2\pi m_h^* kT}{h^2}\right)^{3/2}

Intrinsic concentration (mass action law)

Multiplying nn and pp, the Fermi level cancels:

np=NcNvexp⁡[−Ec−EvkT]=NcNvexp⁡(−EgkT)For intrinsic: n=p=ni  ⇒  ni2=NcNve−Eg/kTni=NcNv exp⁡(−Eg2kT)\begin{aligned} np &= N_c N_v \exp\left[-\frac{E_c - E_v}{kT}\right] = N_c N_v \exp\left(-\frac{E_g}{kT}\right) \\ \text{For intrinsic: } n = p = n_i \;&\Rightarrow\; n_i^2 = N_c N_v e^{-E_g/kT} \\ n_i &= \sqrt{N_c N_v}\, \exp\left(-\frac{E_g}{2kT}\right) \end{aligned}

Since np=ni2np = n_i^2 does not depend on EFE_F, it holds for doped semiconductors too (mass action law). Setting n=pn = p also gives the intrinsic Fermi level EFi=Ec+Ev2+34kTln⁡(mh∗me∗)E_{Fi} = \frac{E_c+E_v}{2} + \frac{3}{4}kT\ln\left(\frac{m_h^*}{m_e^*}\right), which is close to mid-gap.

Effect of temperature

As Nc,Nv∝T3/2N_c, N_v \propto T^{3/2},

ni=C T3/2exp⁡(−Eg2kT)n_i = C\, T^{3/2} \exp\left(-\frac{E_g}{2kT}\right)
  • The exponential term dominates, so nin_i rises very rapidly with TT. For Si (EgE_g = 1.1 eV), nin_i is about 1.45×10101.45\times10^{10} cm⁻³ at 300 K and rises by roughly 2 times for every 8–10 K rise near room temperature.
  • A plot of ln⁡ni\ln n_i against 1/T1/T is nearly a straight line with slope −Eg/2k-E_g/2k; this is used to measure EgE_g.
  • Larger band gap means smaller nin_i (Ge > Si > GaAs at the same TT).
  • Because conductivity σ=nie(μe+μh)\sigma = n_i e(\mu_e + \mu_h), an intrinsic semiconductor's resistance falls sharply with temperature (negative temperature coefficient, used in thermistors).
 ln(ni)
   |\
   | \   slope = -Eg/2k
   |  \
   |   \     Ge
   |    \     \
   |     \ Si  \
   +------------------> 1/T

High nin_i at high temperature is also why doped devices stop working properly above a certain temperature: intrinsic carriers swamp the dopant carriers.

✓ Answer checked by Claude Opus 5.5 (high effort)

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