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n-type carrier concentration versus temperature
Short answer
At low temperature, carrier concentration rises exponentially as donors ionise with slope -ΔE/(2k). In the saturation (extrinsic) region, n ≈ Nd and is nearly constant. At high temperature, intrinsic generation dominates, and n rises steeply with slope -Eg/(2k).
Explain how carrier concentration of an n-type extrinsic semiconductor depends on temperature with necessary diagram and graphs.
In an n-type semiconductor (donor concentration , donor level below the conduction band), the electron concentration changes with temperature through three distinct regions. A plot of against shows them clearly.
ln n
|\
| \ intrinsic
| \ slope -Eg/2k
| \
| \__________________ n = Nd
| extrinsic \
| \ ionisation
| \ slope -ΔE/2k
+----|------------------|------------ 1/T
1/Ti 1/Ts
(high T at left, low T at right)
n
| /
| / intrinsic
| ________________/
Nd | / extrinsic (n = Nd)
| /
| / ionisation
|___/________________________ T
~100K Ts Ti (~500K for Si)
1. Ionisation (freeze-out) region: low T
At very low , electrons are bound to donors. As rises, donors ionise:
Slope of vs is . lies between and .
2. Extrinsic (saturation) region: medium T
Above almost all donors are ionised, and intrinsic generation is still small:
The concentration stays nearly constant. moves slowly towards mid-gap. Devices are designed to operate here (about 150 K to 450 K for Si with cm).
3. Intrinsic region: high T
Above , electrons excited across the band gap outnumber those from donors:
Slope is , much steeper. approaches (mid-gap) and ; the material loses its n-type character.
Fermi level vs temperature
E
Ec |-------------------------
| EF near Ed
| \_
| `-._
Ei |---------`-.__________ (EF -> Ei)
|
Ev |------------------------- T
Summary: rises exponentially, flattens at , then rises again exponentially at high . increases with doping and with band gap.
✓ Answer checked by Claude Opus 5.5 (high effort)
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