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Operators and expectation values of observables

Short answer

In quantum mechanics, operators are mathematical instructions corresponding to observables (e.g., position, momentum, energy). They act on wavefunctions to yield eigenvalues (definite measured values) or expectation values via ⟨A⟩ = ∫ ψ* Â ψ dx, giving average outcomes and enabling uncertainty calculations.

What are the operators in quantum mechanics? Explain their uses in deducing the expected values of observable quantity.

In quantum mechanics an operator is a mathematical instruction that acts on a wave function ψ\psi to give another function. Every measurable (observable) quantity such as position, momentum or energy has a corresponding operator. When the operator acts on ψ\psi and returns a constant times ψ\psi, that constant is the value we would measure.

Common operators

ObservableClassical formOperator
Positionxxx^=x\hat{x} = x
Momentumpxp_xp^x=−iℏ∂∂x\hat{p}_x = -i\hbar \dfrac{\partial}{\partial x}
Kinetic energyp22m\dfrac{p^2}{2m}−ℏ22m∂2∂x2-\dfrac{\hbar^2}{2m}\dfrac{\partial^2}{\partial x^2}
Potential energyV(x)V(x)V(x)V(x)
Total energy (Hamiltonian)p22m+V\dfrac{p^2}{2m} + VH^=−ℏ22m∂2∂x2+V(x)\hat{H} = -\dfrac{\hbar^2}{2m}\dfrac{\partial^2}{\partial x^2} + V(x)
Energy (time form)EEE^=iℏ∂∂t\hat{E} = i\hbar \dfrac{\partial}{\partial t}

Writing H^ψ=E^ψ\hat{H}\psi = \hat{E}\psi gives the Schrödinger equation itself, so the operators are the basis of quantum mechanics.

Eigenvalue equation

If A^ψ=aψ\hat{A}\psi = a\psi with aa a constant, then ψ\psi is an eigenfunction of A^\hat{A} and aa is its eigenvalue. A measurement of AA on this state always gives exactly aa. Example: the time-independent Schrödinger equation H^ψ=Eψ\hat{H}\psi = E\psi gives the allowed energies EE.

Expectation value

In general a state is not an eigenfunction, so repeated measurements give different results. The expectation value is the average of many measurements on identical systems. Since ∣ψ∣2dx|\psi|^2 dx is the probability of finding the particle between xx and x+dxx+dx:

⟨A⟩=∫−∞∞ψ∗ A^ ψ dx∫−∞∞ψ∗ψ dx\langle A \rangle = \frac{\int_{-\infty}^{\infty} \psi^*\, \hat{A}\, \psi \, dx}{\int_{-\infty}^{\infty} \psi^* \psi \, dx}

For a normalised wave function the denominator is 1. Then:

⟨x⟩=∫ψ∗x ψ dx,⟨p⟩=∫ψ∗(−iℏ∂ψ∂x)dx,⟨E⟩=∫ψ∗H^ψ dx\langle x \rangle = \int \psi^* x\, \psi\, dx, \qquad \langle p \rangle = \int \psi^* \left(-i\hbar \frac{\partial \psi}{\partial x}\right) dx, \qquad \langle E \rangle = \int \psi^* \hat{H} \psi\, dx

The operator is placed between ψ∗\psi^* and ψ\psi so that derivatives act only on ψ\psi.

Example: particle in an infinite well

For ψn=2/L sin⁡(nπx/L)\psi_n = \sqrt{2/L}\,\sin(n\pi x/L) in 0≤x≤L0 \le x \le L:

  • ⟨x⟩=2L∫0Lxsin⁡2(nπx/L) dx=L2\langle x \rangle = \frac{2}{L}\int_0^L x \sin^2(n\pi x/L)\, dx = \frac{L}{2}, the centre of the well, as symmetry suggests.
  • ⟨p⟩=0\langle p \rangle = 0, because the particle moves left and right with equal probability.
  • H^ψn=n2h28mL2ψn\hat{H}\psi_n = \frac{n^2h^2}{8mL^2}\psi_n, so ⟨E⟩=En\langle E \rangle = E_n exactly: ψn\psi_n is an energy eigenfunction.

Uses

  1. They give the possible measured values (eigenvalues), e.g. quantised energy levels of electrons in atoms and solids.
  2. They give average values of position, momentum and energy for any state through ⟨A⟩\langle A \rangle.
  3. They allow uncertainties, Δx=⟨x2⟩−⟨x⟩2\Delta x = \sqrt{\langle x^2\rangle - \langle x\rangle^2}, to be calculated, linking to the uncertainty principle.

✓ Answer checked by Claude Opus 5.5 (high effort)

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