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Flexible pavement design with 8 CBR values

Short answer

Design CBR from 90th percentile conservatively taken as 4%. Weighted VDF = 1.95; design traffic after 2.5 years to opening and 10-year life with 7% growth and 75% lane factor: Ns = 2.97 msa. Section adopted from 10-msa catalogue: 40 mm BC, 80 mm DBM, 250 mm WMM base, 330 mm GSB (total 700 mm).

Design a flexible pavement for a two lane highway using provided tables and catalogues. Subgrade CBR values obtained from tests conducted at eight locations are: 11%, 7%, 6%, 7%, 4%, 4%, 8%, and 5%. Total both directional traffic as per last count is 340 CV/day with 60% vehicles of 10000 kg axle load and 40% vehicles of 9000 axle load. Use design life of 10 years, expected completion period of 2.5 years from the date of last count and a traffic growth rate of 7%. State your assumption for estimating the design traffic.

Design method and assumptions

IRC:37-2012 (also followed by Nepal DoR for road pavements) is used.

  • Two-lane single carriageway: design lane carries 50 percent of the two-way commercial traffic as per IRC:37-2012; a more conservative 75 percent (IRC:37-2001) is used here to cover heavier lane loading on a two-lane road.
  • Each commercial vehicle is taken to impose its quoted load on one critical axle (10 000 kg and 9000 kg) and the damage of that axle is counted; standard axle = 80 kN (8160 kg); g=9.81g=9.81 m/s2.
  • Traffic is counted now; the road opens after 2.5 years; design life n=10n=10 years; r=7%r=7\%.

Step 1 - Design CBR

CBR (%)No. equal or greaterPercent equal or greater
48100.0
5675.0
6562.5
7450.0
8225.0
11112.5

The CBR value at which 90 percent of results are equal or greater lies between 4 % (100 percent) and 5 % (75 percent), about 4.4 %. The design subgrade CBR is taken as 4 % (conservative; on the safe side).

Step 2 - Vehicle damage factor (fourth power law)

  • 10 000 kg axle: (10000×9.81/1000 / 80)4=(98.1/80)4=2.261(10000\times9.81/1000\,/\,80)^4=(98.1/80)^4=2.261
  • 9000 kg axle: (88.29/80)4=1.483(88.29/80)^4=1.483
  • Weighted: VDF=0.6×2.261+0.4×1.483=1.950VDF=0.6\times2.261+0.4\times1.483=1.950

Step 3 - Design traffic

Traffic at opening: A=340(1.07)2.5=402.7A=340(1.07)^{2.5}=402.7 CVPD.

Ns=365[(1.07)10−1]0.07×A×D×F=365×13.816×402.7×0.75×1.950=2.97 msaN_s=\frac{365[(1.07)^{10}-1]}{0.07}\times A\times D\times F=365\times13.816\times402.7\times0.75\times1.950=2.97\ \text{msa}

Step 4 - Pavement composition

The lowest design traffic in the IRC:37-2012 catalogues is 10 msa, so for the subgrade CBR of 4 % the 10 msa section is adopted (it is safe for 3 msa; a thinner section can be designed using the IRC:37-2001 plates or IRC:SP:72 if economy is required).

LayerThickness (mm)
Bituminous concrete (BC)40
Dense bituminous macadam (DBM)80
Wet mix macadam (WMM) base250
Granular sub-base (GSB)330
Total700

Answer: design traffic ≈2.97\approx 2.97 msa; section = 40 mm BC + 80 mm DBM + 250 mm WMM + 330 mm GSB over subgrade of CBR 4 %.

✓ Answer checked by Claude Opus 5.5 (high effort)

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