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VDF; four-lane flexible design from catalogue

Short answer

VDF converts vehicle axle loads to equivalent 80-kN standard axle repetitions using fourth-power law. Weighted VDF for the given axle mix = 1.350. Design traffic 20.06 msa (8% growth, 15 years, lane factor 0.75). For CBR 4%, catalogue gives pavement: 40 mm BC, 130 mm DBM, 250 mm granular base, 330 mm sub-base, total 750 mm.

Explain Vehicle Damage Factor (VDF) used in design of flexible pavements. An existing two-lane single carriageway highway is proposed to be widened to a 4-lane divided highway. Design a new flexible pavement for the proposed highway for the following information using provided design catalogues: (i) 4-lane divided carriageway (ii) The expected traffic in the year of completion of construction is 4000 commercial vehicles per day in both direction with 30% heavy trucks of 100kN axle load, 50% light trucks of 80kN axle load, and 20% tractors of 70kN axle load. (iii) Design life = 15 years (iv) Percentage CBR values obtained from seven different locations along the stretch of the highway are 9, 7, 8, 5, 4, 5, 6.5 respectively. (v) Traffic growth rate = 8%

Catalogue for CBR 4% (cumulative traffic msa: total pavement thickness mm; BC mm; DBM mm): 10: 700; 40; 80 | 20: 730; 40; 110 | 30: 750; 40; 130 | 50: 780; 40; 160 | 100: 800; 50; 170 | 150: 820; 50; 190. Granular base = 250 mm and sub-base = 330 mm. Catalogue for CBR 5%: 10: 660; 40; 70 | 20: 690; 40; 100 | 30: 710; 40; 120 | 50: 730; 40; 140 | 100: 750; 50; 150 | 150: 770; 50; 170. Granular base = 250 mm and sub-base = 300 mm.

Vehicle Damage Factor

Vehicle Damage Factor (VDF) is the number of standard axle load repetitions (80 kN single axle) that cause the same damage as one pass of a commercial vehicle. It converts mixed traffic into equivalent standard axles.

  • By the fourth power law, the damage factor of one axle is
EALF=(axle load80 kN)4\text{EALF}=\left(\frac{\text{axle load}}{80\ \text{kN}}\right)^{4}
  • For a vehicle, VDF is the sum of the EALFs of all its axles; for a traffic stream, VDF = ∑ni VDFi∑ni\dfrac{\sum n_i\,\text{VDF}_i}{\sum n_i} (weighted average). Values are obtained from an axle-load survey at the site. If no survey is possible, IRC:37-2012 gives indicative values (for plain terrain 1.5, 3.5 and 4.5 for 0-150, 150-1500 and over 1500 CVPD respectively).
  • Design traffic: Ns=365 [(1+r)n−1]r A D FN_s=\dfrac{365\,[(1+r)^n-1]}{r}\,A\,D\,F, where FF is VDF, AA the initial CVPD, rr the growth rate, nn the design life and DD the lane distribution factor.
  • Overloading in Nepal is common, so a site axle-load survey is preferred to default values.

Design of the 4-lane divided pavement (IRC:37-2012)

Assumptions: each commercial vehicle is represented by its quoted axle load on the critical axle; directional split 50:50; the 4000 CVPD is the traffic in the year of completion, so no construction-period growth is needed.

Step 1 - Design CBR.

CBR (%)No. equal or greaterPercent equal or greater
47100.0
5685.7
6.5457.1
7342.9
8228.6
9114.3

The 90th percentile lies between 4 % (100 percent) and 5 % (85.7 percent): 4+100−90100−85.7×1=4.74+\dfrac{100-90}{100-85.7}\times1=4.7 %. Only the 4 % and 5 % catalogues are provided and 4.7 % is below 5 %, so the design CBR is taken as 4 % (safe side).

Step 2 - VDF (80 kN standard axle):

  • 100 kN: (100/80)4=2.441(100/80)^4=2.441; 80 kN: 1.0001.000; 70 kN: (70/80)4=0.586(70/80)^4=0.586
  • VDF=0.30×2.441+0.50×1.000+0.20×0.586=1.350VDF=0.30\times2.441+0.50\times1.000+0.20\times0.586=1.350

Step 3 - Design traffic. Dual two-lane carriageway: directional share 0.5 and lane factor 0.75 (IRC:37-2012), r=8%r=8\%, n=15n=15 years:

Ns=365×(1.08)15−10.08×4000×0.5×0.75×1.350=365×27.152×1500×1.350=20.06 msaN_s=365\times\frac{(1.08)^{15}-1}{0.08}\times4000\times0.5\times0.75\times1.350=365\times27.152\times1500\times1.350=20.06\ \text{msa}

Step 4 - Section from the CBR 4 % catalogue. The design traffic of 20.06 msa is just above the 20 msa row, so the next higher row (30 msa) is adopted on the safe side. (Linear interpolation between 20 and 30 msa would give practically the 20 msa section: DBM about 110 mm, total 730 mm.)

LayerThickness (mm)
Bituminous concrete (BC)40
Dense bituminous macadam (DBM)130
Granular base (WMM)250
Granular sub-base (GSB)330
Total750

Answer: VDF = 1.350, design traffic ≈\approx 20.06 msa (adopt the 30 msa row); pavement = 40 mm BC + 130 mm DBM + 250 mm base + 330 mm sub-base = 750 mm.

✓ Answer checked by Claude Opus 5.5 (high effort)

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