- Practice · 4+4 marks
Corrosion protection and corrosion rate
Short answer
Four protection methods: coatings, cathodic protection, inhibitors, and alloy selection. Corrosion rate: weight loss 0.45 g, density 7.87 g/cm³, area 12 cm², time 240 h. Thickness lost = 0.45/(7.87×12) = 0.004765 cm = 0.04765 mm. CPR = 0.04765×(8760/240) = 1.74 mm/year.
(a) Describe four methods of protecting metals from corrosion. (b) A mild steel coupon (density 7.87 g/cm) with exposed area 12 cm lost 0.45 g after being immersed in an acid for 240 hours. Calculate the corrosion penetration rate in mm/year.
(a) Corrosion protection methods
- Protective coatings: paint, enamel, plastic, or metallic coatings. Galvanising (zinc on steel) protects both as a barrier and sacrificially, since zinc is anodic to iron even if scratched. Tin plating protects only as a barrier.
- Cathodic protection: make the structure the cathode.
- Sacrificial anode: connect Mg, Zn or Al blocks to buried pipes or ship hulls; they corrode instead of the steel.
- Impressed current: a DC source drives current from an inert anode to the structure.
- Inhibitors: small additions (chromates, phosphates, amines) to the environment that form a protective film or slow the electrode reaction.
- Material selection and alloying: use stainless steel, aluminium, or Cu alloys; design to avoid crevices, galvanic couples, and stagnant water.
- Other: anodising of aluminium, controlling temperature/humidity.
(b) Corrosion rate
Volume of metal lost:
Thickness lost over 240 h:
Hours in a year , so scaling to a year:
This is the same as the standard formula with in mg, in g/cm, in cm, in hours: mm/yr.
Answer: corrosion penetration rate = 1.74 mm/year (about 68 mpy).
✓ Answer checked by Claude Opus 5.5 (high effort)
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