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Corrosion protection and corrosion rate

Short answer

Four protection methods: coatings, cathodic protection, inhibitors, and alloy selection. Corrosion rate: weight loss 0.45 g, density 7.87 g/cm³, area 12 cm², time 240 h. Thickness lost = 0.45/(7.87×12) = 0.004765 cm = 0.04765 mm. CPR = 0.04765×(8760/240) = 1.74 mm/year.

(a) Describe four methods of protecting metals from corrosion. (b) A mild steel coupon (density 7.87 g/cm3^3) with exposed area 12 cm2^2 lost 0.45 g after being immersed in an acid for 240 hours. Calculate the corrosion penetration rate in mm/year.

(a) Corrosion protection methods

  1. Protective coatings: paint, enamel, plastic, or metallic coatings. Galvanising (zinc on steel) protects both as a barrier and sacrificially, since zinc is anodic to iron even if scratched. Tin plating protects only as a barrier.
  2. Cathodic protection: make the structure the cathode.
    • Sacrificial anode: connect Mg, Zn or Al blocks to buried pipes or ship hulls; they corrode instead of the steel.
    • Impressed current: a DC source drives current from an inert anode to the structure.
  3. Inhibitors: small additions (chromates, phosphates, amines) to the environment that form a protective film or slow the electrode reaction.
  4. Material selection and alloying: use stainless steel, aluminium, or Cu alloys; design to avoid crevices, galvanic couples, and stagnant water.
    • Other: anodising of aluminium, controlling temperature/humidity.

(b) Corrosion rate

Volume of metal lost:

V=Wρ=0.457.87=0.05718 cm3V = \frac{W}{\rho} = \frac{0.45}{7.87} = 0.05718\ \text{cm}^3

Thickness lost over 240 h:

x=VA=0.0571812=0.004765 cm=0.04765 mmx = \frac{V}{A} = \frac{0.05718}{12} = 0.004765\ \text{cm} = 0.04765\ \text{mm}

Hours in a year =8760= 8760, so scaling to a year:

CPR=0.04765×8760240=0.04765×36.5=1.74 mm/yearCPR = 0.04765 \times \frac{8760}{240} = 0.04765 \times 36.5 = 1.74\ \text{mm/year}

This is the same as the standard formula CPR=87.6 WρAtCPR = \dfrac{87.6\,W}{\rho A t} with WW in mg, ρ\rho in g/cm3^3, AA in cm2^2, tt in hours: 87.6×4507.87×12×240=1.74\dfrac{87.6 \times 450}{7.87 \times 12 \times 240} = 1.74 mm/yr.

Answer: corrosion penetration rate = 1.74 mm/year (about 68 mpy).

✓ Answer checked by Claude Opus 5.5 (high effort)

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