Why is no correction needed?

Sum of latitudes and sum of departures are both zero

Departures are bigger than latitudes

What check is available on the DMDs?

The DMD of the last line equals its departure with opposite sign

The first and last DMDs are equal

The last DMD equals the last latitude

81969 m^2, taking half the absolute value

Short answer

DMDs: 202, 484, 232, −401, −351 m; Σ(L×DMD) = −163938 m². Area = 81969.00 m² (8.1969 ha).

Calculate the area of the traverse by double meridian distance method.

Line	AB	BC	CD	DE	EA
Latitude (m)	+218	-277	-109	-207	+375
Departure (m)	+202	+80	-332	-301	+351

The traverse closes: ΣL = 0 and ΣD = 0.

DMD rule (taking the meridian through the starting station):

DMD of the first line = departure of the first line.
DMD of any line = DMD of the previous line + departure of the previous line + departure of the line itself.
DMD of the last line = departure of the last line with opposite sign (a check).
Double area = Σ (latitude × DMD), and area = ½ |Σ L × DMD|.
DMD(AB) = D(AB) = 202
DMD(BC) = 202 + (202) + (80) = 484
DMD(CD) = 484 + (80) + (-332) = 232
DMD(DE) = 232 + (-332) + (-301) = -401
DMD(EA) = -401 + (-301) + (351) = -351
Check: DMD(EA) = -351 = −D(EA) = -351, so the DMDs are correct.

Line	Latitude L (m)	Departure D (m)	DMD (m)	L × DMD (m²)
AB	218	202	202	44036
BC	-277	80	484	-134068
CD	-109	-332	232	-25288
DE	-207	-301	-401	83007
EA	375	351	-351	-131625
Sum	0	0		-163938

\text{Area} = \frac{|-163938|}{2} = 81969\ \text{m}^2

Answer: Area = 81969.00 m² (8.1969 ha).

✓ Answer checked by Claude Opus 5.5 (high effort)